by the wind and air flow in the wind
Given:
Circumference = 2 m
Angular speed, ω = 1 rev/s = 2π radians/s
If the radius is r, then
2πr = 2
r = 1/π m
The linear (tangential) speed is
v = rω
= (1/π m)*(2π rad/s) = 0.5 m/s
Answer: 0.5 m/s
However here coefficient of friction is not given so unable to calculate.
You can calculate it by below formula.
The formula given by
Or
u is coefficient of friction
N is normal reaction.
Here..
box doesn't move means the force if limiting friction is greater than applied force.
The force on the box is:
F = mgsin∅
If we multiply by this with the distance it traveled, we will know the work done by the box.
W = dmgsin∅
This work will be converted to elastic potential energy in the spring which is:
1/2 kx². Equating these and substituting values:
1/2 * 170 * x² = 4 * 13 * 9.81 * sin(30)
x = 1.73 m
The box's maximum speed will at the point right before contact with the spring, when the compression is 0.
