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pav-90 [236]
3 years ago
15

Dos láminas, una de cobre y otra de hierro, se encuentran soldadas y empotradas enuna pared como lo muestra la figura 13. Si las

láminas se encuentra a 20 ºC ysabiendo que el coeficiente de dilatación térmica del cobre es mayor que el hierro,entonces se podría predecir que a una temperatura de 100 ºC
A) El extremo libre se doblará hacia A.
B) el extremo libre se doblará hacia B.
C) las láminas se dilatarán sin doblarse.
D) las láminas se contraerán sin doblarse.
E)la lámina de coeficiente de dilatación térmica menorimpedirá la dilatación de la otra.
Physics
1 answer:
PolarNik [594]3 years ago
7 0

Answer:

umm i gotta put this in English!!!!!

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Determine the projection (magnitude and sign), or component, of vector v1 along the direction of vector v2. Your answer could be
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Answer:

- 1.07 ft

Explanation:

V1 = (-5, 7, 2)

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Projection of v1 along v2, we use the following formula

=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}

So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4

The magnitude of vector V2 is given by

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So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft

Thus, the projection of V1 along V2 is - 1.07 ft.

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3 years ago
Line segment gj is a diameter of circle l. angle k measures (4x 6)°. circle l is inscribed with triangle g j k. line segment g j
choli [55]

The value of x in the given right triangle in a semicircle is determined as 21.

<h3>What is the measure of a triangle in a semicircle?</h3>

The triangle in a semicircle is always a right angle triangle.

From the figure shown, we can say that the triangle  G J K is right triangle and m<K = 90degrees.

Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:

4x + 6 = 90

4x = 90 - 6

4x = 84

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Thus, the value of x in the given right triangle in a semicircle is determined as 21.

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2 years ago
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Answer:

heliocentric is when the earth and the other planets revolves around the sun.

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3 years ago
Each plate of an air-filled parallel-plate capacitor has an area of 45.0 cm2, and the separation of the plates is 0.080 mm. A ba
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Answer:

Option (e)

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Energy density = 1/2 x ε0 x E^2

100 = 0.5 x 8.854 x 10^-12 x E^2

E = 4.75 x 10^6 V/m

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Q =  190 nC

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3 years ago
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