Since there is no phase change, we can use the heat equation,
Q = mcΔT
where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J kg⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

Q = 2000 J
m = 100 g = 0.1 kg
c = ?
ΔT = (70 °C - 50 °C) = 20 °C

By applying the formula,
2000 J = 0.1 kg x c x 20 °C
c = 2000 J / (0.1 kg x 20 °C)
c = 1000 J kg⁻¹ °C⁻¹

Hence, the specific heat capacity of the liquid is 1000 J kg⁻¹ °C⁻¹.

5 0

4 years ago

How many moles are there in 45.0 grams of sulfuric acid,<br> H2SO4?<br> moles

nydimaria [60]

Answer:

0.459 mol

Explanation:

M(H2SO4) = 2*1 + 32 +4*16 = 98 g/mol

45.0 g * 1 mol/98 g = 0.459 mol

7 0

4 years ago

To test a hypothesis, Robin needed to make sure the temperature outside what at least 10° above freezing. What tool did she use

Molodets [167]

thermometer my friend since it is a measureful device

thanx

heyaaaa

7 0

3 years ago

Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .

A solution is acidic if $\rm [H_3O^{+}] > [OH^{-}]$ .
A solution is neutral if $\rm [H_3O^{+}] = [OH^{-}]$ .
A solution is acidic if $\rm [H_3O^{+}] < [OH^{-}]$ .

$\rm [H_3O^{+}] > [OH^{-}]$ for this solution. As a result, this solution is acidic.

8 0

3 years ago