Answer:
<h2>The species that furnishes the electrons is called the reducing agent. In this case, the reducing agent is zinc metal.</h2>
Explanation:
<h2>Hopes this helps. Mark as brainlest plz!</h2>
Answer:
highest first ionization energy - Br
smallest atomic size - Br
most metallic character - Na
Explanation:
Ionization energy of Br is higher than P because higher zeff value
Sodium is more metallic than calcium because it is able to loose electron more readily as compared to calcium because of higher electro positivity.
Atomic radius of Br is the smallest as its atomic radius is 114, P (115), Ca (197), Na (186)
<span> iron (Fe), ruthenium (Ru), osmium (Os) and hassium (Hs). They are all transition metals.</span>
Answer:
Percent yield: 78.2%
Explanation:
Based on the reaction:
4Al + 3O₂ → 2Al₂O₃
<em>4 moles of Al produce 2 moles of Al₂O₃</em>
<em />
To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:
(Actual yield (6.8g) / Theoretical yield) × 100
Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:
4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.
As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:
0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,
In grams (Molar mass Al₂O₃ = 101.96g/mol):
0.0852 moles of Al₂O₃ × (101.96g / mol) =
<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>
Thus, Percent yield is:
(6.8g / 8.7g) × 100 =
<h3>
78.2% </h3>
Mercury and carbon two electrodes can't be used with an inactive or inert material.
<h3>What is an electrode?</h3>
The electrode is the element which is used to complete the electric circuit in welding. Some time electrode is connected with the positive terminal and sometimes with a negative terminal, it depends on the requirement of the welding process.
Inert electrode is an electrode that serves only as a source or sink for electrons without playing a chemical role in the electrode reaction. Precious metals, mercury, and carbon are typically used as inert electrodes.
Therefore, neither of the two electrodes can be used with an inactive or inert material.
Learn more about electrodes here:
brainly.com/question/13098144
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