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Vaselesa [24]
4 years ago
9

A band of blue light has a velocity of 3.0 x 108

Physics
1 answer:
mr_godi [17]4 years ago
4 0

Answer: 6.4 x 10^14Hz

Explanation:

velocity of blue light (V) = 3.0 x 10^8m/sec

wavelength (λ) = 465 nanometers

(4.65 x 10?m)

Since 1nanometer = 1 x 10^-9 meter

465 nanometer = 4.65 x 10^-7 meters

frequency (F) = ?

Recall that the frequency of a wave is the number of cycles the wave complete in one second, and its unit is Hertz.

So, apply the formula V = F λ

3.0 x 10^8m/sec = F x 4.65 x 10^-7 meters

F = (3.0 x 10^8m/sec / 4.65 x 10^-7 meters)

F = 6.4 x 10^14Hz

Thus, the frequency of the blue light is 6.4 x 10^14Hz

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What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma
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E = 1.50 × 10^{8} V/m

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given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

\mu _b = \frac{B}{2\mu _o}   ...............1

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energy density due to electric filed is

\mu _e = \frac{\epsilon _o E^2}{2}     ...............2

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