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Andreyy89
3 years ago
12

You get pulled over for running a red light. You explain to the police officer that the light appeared green to you due to the D

oppler effect. The police officer writes you a ticket for speeding instead. The fine is $100 for every 10km/hr over the speed limit of 60km/hr you were traveling. How much is the speeding ticket?
Physics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

$ 3085713685.71

Explanation:

\lambda_0 = Actual wavelength = 700 nm

\lambda = Changed wavelength = 500 nm

Let the wavelength of red color be 700 nm and green be 500 nm

Change in wavelength is

\Delta \lambda=700-500\\\Rightarrow \theta\lambda=200\ nm

We have the relation

\dfrac{\Delta\lambda}{\lambda_0}=\dfrac{v}{c}\\\Rightarrow v=\dfrac{\Delta\lambda}{\lambda_0}c\\\Rightarrow v=\dfrac{200}{700}\times 3\times 10^8\\\Rightarrow v=85714285.7143\ m/s

The speed of the vehicle is 85714285.7143 m/s

\dfrac{85714285.7143\times 3600}{1000}=308571428.571\ km/h

By how much was the car speeding

308571428.571-60=308571368.571\ km/h

The number of 10 km/h in the above speed

308571368.571\times\dfrac{1}{10}=30857136.8571

Cost of the ticket

30857136.8571\times 100=\$ 3085713685.71

The cost of the ticket is $ 3085713685.71

mr Goodwill [35]3 years ago
5 0

Answer:

not enough info

Explanation:

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3 years ago
a 13-gram bullet, moving at 270 m/s, penetrates a 2 kg block of wood and emerges at a speed of 130 m/s. if teh block sits one a
saveliy_v [14]

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1.52m/s

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6 0
3 years ago
A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
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<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
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   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
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6 0
3 years ago
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