Answer: 0.4 moles
Explanation:
Given that:
Amount of moles of HCI = Z (let unknown value be Z)
Volume of HCl = 500.0 mL
Convert 500.0 mL to liters
If 1000ml = 1L
500.0 mL = (500.0 mL/1000mL) = 0.5L
Molarity of HCl solution = 0.200M
Recall that molarity of a solution is obtained by dividing the amount of moles by volume in liters
i.e Molarity = Amount in moles/volume
0.200M = Z x 0.5L
Z = 0.200M / 0.5L
Z = 0.4 moles
Thus, 0.4 moles of HCl is needed to make the solution
I'm pretty sure its Sankey Diagram.
(Edit: Turned Dankey to Sankey which is the proper name for the diagram)
<h2>Given :-</h2>
<h2>To Find :-</h2>
<h2>Solution :-</h2>
As we know that
PV = nRT
Here,
- P = Pressure
- V = Volume
- n = Moles
- T = Temperature
<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>
- 1.25 × 25 = 2.1 × 0.082 × T
- 31.25 = 2.1 × 0.082 × T
- 31.25 = 1.722T
- 31.25/0.1722 = T
- 181 ≈ T
Temperature is 181 K
Answer:
EASSSSSYYY give me a harder question smh
if you want you can give me Brainliest answer lol
Explanation:
A solid’s particles are packed closely together. The forces between the particles are strong enough that the particles cannot move freely.
A liquid is a fluid that conforms to the shape of its container but that retains a nearly constant volume independent of pressure. The volume is definite (does not change) if the temperature and pressure are constant.
Gas molecules have either very weak bonds or no bonds at all, so they can move freely and quickly. Because of this, not only will a gas conform to the shape of its container, it will also expand to completely fill the container.
Answer:
Approximately 206 grams.
Explanation:
How many moles of sulfuric acid 
are there in this solution?
.
The unit for concentration "
" is equivalent to mole per liter. In other words, 
. For this solution, the concentration of is 
.
.
What's the mass of that 
of ?
Start by finding the molar mass 
of .
Relative atomic mass data from a modern periodic table:
- H: 1.008;
- S: 32.06;
- O: 15.999.
.
.
.
In other words, the chemist shall need approximately 206 grams of to make this solution. As a side note, keep in mind that the 206 grams of also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.
