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STALIN [3.7K]
2 years ago
9

A cyclical heat engine, operating between temperatures of 450º C and 150º C produces 4.00 MJ of work on a heat transfer of 5.00

MJ into the engine. How much heat transfer occurs to the environment? (b) What is the efficiency of the engine?
Physics
1 answer:
gogolik [260]2 years ago
5 0

Answer:

(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%

Explanation:

Using the formula that relate heat and work from the thermodynamic theory as:W=Q=Q_{in}-Q_{out} solving to Q_out we get:Q_{out}=Q_{in}-W=5(MJ)-4(MJ)=1(MJ) this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us: n=1-\frac{T_{Low} }{T_{High}} where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get:n=1-\frac{423.15}{723.15} =0.415=41.5%

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sleet_krkn [62]

Answer:

I will explain the concept of magnetic field and how it can be calculated.

Explanation:

The formula for magnetic field at the center of a loop is given as

B = μ_{o}I / 2R

where B is the magnetic field

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3 0
3 years ago
. Light travels at a speed of about 300 000 km/s. a. Express this value in scientific notation. b. Convert this value to meters
olganol [36]

Answer:

The answer to your question is below

Explanation:

Data

light speed = 300 000 km/s

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to do it, we just move the decimal point 5 places to the left

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  (300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1

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c) What distance in centimeters does light travel in 1 s?

data

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d = ?

t = 1 s

 formula   v = d/t      we clear distance     d = vxt

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4 0
3 years ago
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147.456077993 Hz

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The difference in frequency is given by

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Explanation:

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