Answer:
Empirical formula is NH₃
Explanation:
Given data:
Percentage of hydrogen = 82%
Percentage of nitrogen = 18%
Empirical formula = ?
Solution:
Number of gram atoms of H = 18 / 1.01 = 17.8
Number of gram atoms of N = 82 / 14 = 5
.9
Atomic ratio:
H : N
17.8/5.9 : 5.9/5.9
3 : 1
H : N = 3:1
Empirical formula is NH₃
Answer:
a) 300 L
b) 100 L
c) 12000 L
Explanation:
a) Amount of water required for 1 kg of Paper = 300 - 400 Kgs or liters
Amount of water water required for 1 Kg of steel = 704.9 L
It takes 300 L more water
b) Amount of water required for 1 kg Potato = 300 liters
It takes 100 L more water
c) Amount of water required for 1 kg Potato = 300 liters
Amount of water required for 1 kg beef = 15,415 liters
It takes 12000 L more water
Density of boat =
=
= 0.88 g / cm³
Since the density of water is greater than the density of the boat ( 1 > 0.88) then that means,
the boat will NOT sink.B.
Explanation:
The formula of nitrogen gas is given as;
N₂
Given volume of the gas = 120cm³
Now,
We need to find the number of molecules and the mass of this compound
Solution:
At STP;
1 mole of gas occupies a volume of 1dm³ ;
1000cm³ = 1dm³
120cm³ gives 0.12dm³;
Now;
1dm ³ of gas contains 1 mole of substance at STP
0.12dm³ will contain 0.12mole of nitrogen gas at STP
Mass of N₂ gas = number of moles x molar mass of N₂
Molar mass of N₂ = 2(14) = 28g/mol
Mass of N₂ = 0.12 x 28 = 3.36g
1 mole of a substance contains 6.02 x 10²³ molecules
0.12 mole of N₂ will contain 0.12 x 6.02 x 10²³ = 7.22 x 10²²molecules
<h3>
Answer:</h3>
#a. ⁵¹₂₂Ti + ⁰₋₁e → ⁵¹₂₃V
#b. 0.0977 g
<h3>
Solution and explanation:</h3><h3>
#a.</h3>
- Titanium-51 is the radioisotope that undergoes Beta emission to emit a daughter isotope Vanadium-51 (Mass number-51 and atomic number -23).
- Titanium-51 has a mass number of 51 and atomic number of 22.
- A beta particle is equivalent to ⁻¹₀e
- Beta emission does not affect the mass number of an isotope but increases the atomic number by 1.
Therefore;
The reaction will be;
⁵¹₂₂Ti + ⁻¹₀e → ⁵²₂₂V
<h3>#b. </h3>
The half life of Ti-51 is 6 minutes
We can calculate the mass remaining after 1 hour (60 min)
Original mass of the sample = 10.0 g
But; using the formula;
Remaining mass = Original mass × (1/2)^n , where n is the number of half lives.
in this case, n = time/half life
= 60 min ÷ 6 min
= 10
Therefore;
Remaining mass = 100 g × (1/2)^10
= 0.0977 g
Therefore, the mass of Ti-51 remaining after 1 hour will be 0.0977 g