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mario62 [17]
2 years ago
6

A northbound train and a southbound train meet each other on parallel tracks heading in opposite directions. The northbound trai

n travels 16 miles per hour faster than the southbound train. After 1.5 hours, they are 174 miles apart. At what speeds are the two trains traveling?
Physics
2 answers:
SSSSS [86.1K]2 years ago
4 0

Answer:

50mph,60mph

Explanation:

Let speed of southbound train=x mph

Speed of northbound train,y=x+16 mph

Distance between two trains after 1.5 hour,174 miles.

We have to find the speed of two trains.

Distance=speed\times time

Using the formula

174=1.5x+1.5(x+16)

174=1.5(x+x+16)

174=(2x+16)\times 1.5

174=3x+24

3x=174-24=150

x=\frac{150}{3}=50mph

y=x+16=50+16=66mph

marta [7]2 years ago
3 0

Answer

Given,

Let the speed of the slower train be x mph.

speed of faster train be (x+16) mph.

time, t = 1.5 hr

d₁ = 1.5 x

d₂ = (x+16)× 1.5

both train are traveling in opposite direction

d₁  + d₂ = 174

1.5 x +  (x+16)× 1.5 = 174

3 x + 24 = 174

3 x = 150

x = 50

Speed of the slower train is 50 mph

Speed of the faster train is (50+16) = 66 mph.

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By using an electric field, it is feasible to differentiate between these different forms of radiation.

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A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.

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An open diving chamber rests on the ocean floor at a water depth of 60 meter. Find the air pressure (gage pressure relative to t
Fofino [41]

Answer:

Gauge Pressure required = 606.258 kPa

Explanation:

Water will not enter the chamber if the pressure of air in it equals that of the water which tries to enter it.

Thus at a depth of 60m we have pressure of water equals

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Now the gauge pressure is given by

P(z)-P_{0}=\rho _wgh

Applying values we get

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8 0
3 years ago
Due today HELP HELP HELP
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Vas happenin!

Independent variable : amount of water each day

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A 10-ft ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 2 ft/sec, how fast is the b
netineya [11]

Answer: The bottom of the ladder is moving at 3.464ft/sec

Explanation:

The question defines a right angle triangle. Therefore using pythagorean

h^2 + l^2 = 10^2 = 100 ...eq1

dh/dt = -2ft/sec

dl/ dt = ?

Taking derivatives of time in eq 1 on both sides

2hdh/dt + 2ldl/dt = 0 ....eq2

Putting l = 5ft in eq2

h^ + 5^2 = 100

h^2 = 25 = 100

h Sqrt(75)

h = 8.66 ft

Put h = 8.66ft in eq2

2 × 8.66 × (-2) + 2 ×5 dl/dt

dl/dt = 17.32 / 5

dl/dt = 3.464ft/sec

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3 years ago
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