Answer:
a) 2.4 mm
b) 1.2 mm
c) 1.2 mm
Explanation:
To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:

a: width of the slit
λ: wavelength
m: order of the minimum
for little angles you have:

y: height of the mth minimum
a) the width of the central maximum is 2*y for m=1:

b) the width of first maximum is y2-y1:
![w=y_2-y_1=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[2-1]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_2-y_1%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B2-1%5D%3D1.2mm)
c) and for the second maximum:
![w=y_3-y_2=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[3-2]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_3-y_2%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B3-2%5D%3D1.2mm)
Answer:
The Answer is gonna be According D.separate atoms from their electrons
I believe the answer is Mouse/Herbivore. It was a question in my old lab haha.
Hope this helped!!
~xox Melis
Answer:
The power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
Explanation:
Given;
three identical resistors connected in series
let the first resistor = R₁
let the second resistor = R₂
let the third resistor = R₃
Rt = R₁ + R₂ + R₃
Since the resistors are identical, thus, R₁ = R₂ = R₃ = R
Rt = 3R
Power is given as;
P = IV = V² / R

If the 3 identical resistor connection were changed to parallel, then the equivalent resistance in the circuit will be;


Therefore, the power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W
Answer:
gravitational field strength (g) is measured in newtons per kilogram (N/kg)