Homogeneous - the mixture is even throughout the solution cannot tell one part from another
heterogenous - the mixture is not mixed even and you can tell one compound from another.
NaCl is a homogeneous solution since you cannot visibly separate the NaCl from the water it is dissolved in.
We're given the velocity at two points, and the time between the mentioned two points.
What we'll be calculating is the average acceleration (not to be confused with instantaneous acceleration).
Given two points, lets call them initial and final, the average acceleration is calculated as:
In which
is the final velocity (in your problem equal to 1m/s),
is the initial velocity (in your problem equal to 16 m/s), and
the time between two points (in your problem equal to 2s).
So, we plug-in our known values:
The answer is -7.5m/s^2.
A good way to do that is to talk abt anything, TALK MORE NOT LESS:)
Electromagnetic
radiation are represented in waves. Each type of wave has a certain shape and
length. The distance between two peaks in a wave is called the wavelength. This
value is equal to the speed of light divided by the frequency.
<span>
Wavelength = c/f
</span><span>5.8 x 10^-7 = 3x10^8 / f
</span><span>
f = 2.2 x 10^14 Hz
</span>
Answer:
below the horizontal.
Explanation:
This is a projectile motion problem. So we are going to use uniform motion and free-fall formulas.
Since what we want is the angle of the diver when hitting the water, we are going to search for the components of the final velocity and with them compute the angle.
For the free-fall part we know:
- ,
- ,
- (remember that the initial velocity in the vertical component is zero because at the begining he only has horizontal velocity).
For the uniform motion part:
Notice that we already have the final velocity in the x coordinate (uniform motion means that the velocity is constant).
For the final velocity in y coordinate we are going to use:
,
since we get
,
,
,
.
Now we can find the angle using the tangent function and the components of the final velocity. Remember that they are related as follow:
,
where is the angle below the horizontal (the angle we are searching for).
We have that
.