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Sav [38]
2 years ago
11

HCI + NaOH .-> Nacl + H2O what is the Mole ratio of acid to alkali ?​

Chemistry
2 answers:
Irina-Kira [14]2 years ago
7 0

Answer:

........

it is 1:1 thank you

Anettt [7]2 years ago
7 0
  • Moles of Na=1
  • Moles of Acid=1

Lets check what are present here

  • Acid=HCl
  • Base=NaOH
  • Salt=NaCl

Ratio=1:1

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Consider the reaction. mc015-1.jpg How many grams of N2 are required to produce 100.0 L of NH3 at STP?
Nadusha1986 [10]
The  grams  of N2  that  are   required   to  produce 100.0 l  of  NH3   at  STP

At  stp 1moles = 22.4  l. what  about  100.0 L of NH3

= 100 / 22.4 lx1  moles = 4.46  moles  of NH3

write the reacting  equation

N2+3H2 =2NH3
by use of mole  ratio  between  N2  to NH3  which is  1:2 the moles of N2 =4.46/2 =2.23  moles of N2

mass =  moles  x  molar  mass

=  2.23moles  x 28  g/mol =  62.4 grams
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3 years ago
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I believe the correct response would be A. The cumulative nature of science. How experimental evidence and ideas made by many scientists have accumulated and or built up to have a more understandable and or clear view of a particular scientific topic, and or principle.
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Which 5.0-milliliter sample of NH3 will take the shape of and completely fill a closed 100.0-milliliter container?(1) NH3(s) (3)
antoniya [11.8K]
NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container. 
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3 years ago
The substances below are listed by increasing specific heat capacity value. Starting at 30 Celsius, they absorb 100 kJ of therma
Georgia [21]

Answer:

Silver.

Explanation:

To obtain the right answer to question, let us calculate the change in temperature for each substance assuming they all have the same mass as 100g.

This is illustrated below:

1. For Siver:

Mass (M) = 100g

Specific heat capacity (C) = 0.239J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 0.239)

ΔT = 4184°C

2. For Aluminium:

Mass (M) = 100g

Specific heat capacity (C) = 0.921J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 0.921)

ΔT = 1086°C

3. For Lithium:

Mass (M) = 100g

Specific heat capacity (C) = 3.56J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 3.56 )

ΔT = 281°C

4. For water:

Mass (M) = 100g

Specific heat capacity (C) = 4.184J/g°C

Heat (Q) = 100 kJ = 100000J

Change in temperature (ΔT)

Q = MCΔT

ΔT = Q/MC

ΔT = 100000/(100 x 4.184)

ΔT = 239°C

Summary

Temperature change of each substance is given below

1. Silver => 4184°C

2. Aluminum => 1086°C

3. Lithium => 281°C

4. Water => 239°C

From the calculations made above, Silver has the highest rise in temperature.

4 0
3 years ago
2) A balloon was inflated to a volume of 5.0 liters at a temperature of
TEA [102]

Answer:

6.12 L

Explanation:

Given that,

Initial volume, V₁ = 5 L

Initial temperature, T₁ = 7.0°C = 343 K

Final temperature, T₂ = 147°C = 420 K

We need to find its new volume. The relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{5\times 420}{343}\\\\V_2=6.12\ L

So, the new volume is 6.12 L.

8 0
2 years ago
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