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rosijanka [135]
3 years ago
13

Answer this question

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

i) 2

ii) No

Explanation:

i) The man will hear two sounds: one through the rail, and one in the air.

ii) The sounds will not reach the man at the same time.  Sound travels faster through solids than through gases, so he will hear the sound through the rail before he hears the sound in the air.

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In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10
olchik [2.2K]
I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
\epsilon = -N \frac{\Delta \Phi}{\Delta t}
where
N is the number of turns in the coil
\Delta \Phi is the variation of magnetic flux through the coil
\Delta t is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
\Phi_f = 0

Therefore, we can calculate now the induced emf by using the first formula:
\epsilon = -N  \frac{\Delta \Phi}{\Delta t}=- (250)  \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V
7 0
4 years ago
Who got the energy conversation in a system gizmo answers dm me on insta .al3xgonrockout​
Mars2501 [29]

Answer:

a

Explanation:

3 0
3 years ago
HERES THE ANSWER AND QUESTION
tatyana61 [14]

Answer:

agree

Explanation:

5 0
3 years ago
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To view an enlarged upright image of an object through a simple magnifier, where must the object be located?.
Andre45 [30]

Answer:within the focal length of the lens, provided the focal length is shorter than the near point distance.

Explanation:Hope it helps

6 0
3 years ago
The velocity field of a flow is given by V = 3x2ti+[4y(t-1)+3x2t] j m/s, where x and y are in meters and t is in seconds. For fl
Katena32 [7]

Answer:

See explanations

Explanation:

Given that,

Electric field E=135V/m

Energy stored in 1m³of air=?

The energy stored in an electric field is given as

u = ½ εo E²

Where

U is the energy stored

εo is permissivity and it value is 8.85×10^-12C²/N..m²

And E is the electric field

Then,

U=½×8.85×10^-12×135²

U=8.06×10^-8J/m³

Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³

6 0
4 years ago
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