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Mazyrski [523]
3 years ago
5

A car is traveling at 40 m/s. The brakes are applied an after 3 seconds the car is traveling 13 m/s. What is the acceleration of

the car?
Physics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

- 9m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Time taken  = 3s

Final velocity  = 13m/s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time taken.

   Acceleration  = \frac{Final velocity  - Initial velocity }{Time taken}  

  Acceleration  = \frac{13  - 40 }{3}   = - 9m/s²

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alukav5142 [94]

Answer:

The time taken is 6.7  min

Explanation:

Using the linear momentum conservation theorem, we have:

m_1*v_{o1}+m_2*v_{o2}=m_1*v_{f1}+m_2*v_{f2}

when she was 60.4m from the shuttle, she has zero speed, so the initial velocity is zero.

m_1*0+m_2*0=m_1*v_{f1}+m_2*v_{f2}\\m_1*_{f1}=-m_2*v_{f2}\\v_{f1}=-\frac{m_2*v_{f2}}{m_1}\\\\v_{f1}=-\frac{0.886kg*12m/s}{69.8kg}\\\\V_{f1}=-0.15m/s

That is 0.15m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

t=\frac{d}{v_{f1}}\\\\t=\frac{60.4m}{0.15m/s}\\\\t=403s\\t_{min}=403s*\frac{1min}{60s}=6.7min

6 0
3 years ago
Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency res
aleksandr82 [10.1K]

Answer:

The percentage change in frequency is 10%.

Explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

\Delta f=\Delta A\times R

Put the value into the formula

\Delta f=\dfrac{1}{10}\times10

\Delta f=1\ Hz

We need to calculate the resonant frequency

Using formula of resonant frequency

f_{r}=R-\Delta f

Put the value into the formula

f_{r}=10-1

f_{r}=9\ Hz

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

f=\dfrac{10-9}{10}

f=10\%

Hence, The percentage change in frequency is 10%.

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4 years ago
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Hydrogen, helium, and carbon.
8 0
3 years ago
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A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of
Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

F=ILB sin \theta

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

\theta is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

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Substituting into the equation, we find

F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N

6 0
3 years ago
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