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Vikki [24]
4 years ago
7

When you pick a book up off the floor you are tranfering __________ energy from your hands to the ____________ energy of the boo

k. A chemical B kinetic C light D potential E radiant F thermal
Physics
1 answer:
MakcuM [25]4 years ago
3 0
When you pick a book off the floor you are transferring kinetic energy from your hands to the potential energy of the book.
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A proton enters a uniform magnetic field of strength 0.5 T at 200 m/s. The magnetic field is oriented at an angle of 30° to the
-BARSIC- [3]
<h2>The force experienced is 8 x 10⁻¹⁸ N</h2>

Explanation:

When any charge moves into the magnetic field , it experiences the force

The force can be calculated by the relation F = q v B sinθ

here q is the charge and v is its velocity .

B is magnetic field strength and θ is the angle between field and velocity vectors .

Thus F = 1.6 x 10⁻¹⁹ x 200 x 0.5 x  sin 30

=  8 x 10⁻¹⁸ N

8 0
4 years ago
What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27
gayaneshka [121]

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

8 0
3 years ago
The normal boiling point of water is 100.0 °c and its molar enthalpy of vaporization is 40.67 kj/mol. what is the change in entr
SashulF [63]
ΔS= nΔHvap/T,

Where, ΔS = Change in entropy, n = moles of water = 39.3/18 = 2.188 moles, ΔHvap = 40.67kJ/mol = 40670 J/mol, T = Temperature (K) = 100+272.15 = 373.15 K

Therefore,
ΔS = (2.188*40670)/373.15 = 237.96 J/K
6 0
3 years ago
Compare the speed of a moving golf ball with the speed of a moving bowling ball if both balls have the same amount of momentum.
Kitty [74]

Answer:

The speed of the golf ball is much greater than the speed of the bowling ball.

Explanation:

7 0
3 years ago
an object which has a mass of 70 kg is sitting on a cliff 10 m high calculate the objects gravitational potential energy given g
Alex73 [517]
GPE = mgh (for objects close to earth where g can be considered to be constant) Where m is the mass, g is the acceleration due to gravity (which the question has told us to assume is 10ms^-2), and h is the height of the object.

Substituting the values in:
GPE = 70*10*10 = 7000J
5 0
3 years ago
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