If a molecule is found to have four hybrid sp3 then we say that it has a <span>tetrahedral molecular geometry. thsi is the correct term to define this type of molecules. So your option would be C. Hope this is useful</span>
First convert grams to kilograms (so that the answer will be N) 1000g=1kg so 2.9g=.0029kg.
To solve for force we use the equation F=ma, so we need to find acceleration (a) .Next use the equation a=Δv/Δt. Δt is given as being .00043 seconds. Δv is the difference in velocities - final minus initial (this is important to discern the direction of the force vector); 0-304=-304. Now plugin and solve for a. The result is -706976.7442 m/s², or -710000 m/s² if you are using significant figures.
Now use the values for mass and acceleration to solve for force. F=ma=-2050.232558N or F=- 2100N (if you are using significant figures).
Answer:
1.99 parsecs.
Explanation:
We have been given that the most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-years.
We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.



Therefore, Luhman 16 is approximately 1.99 parsecs away from the Earth.
Answer:
bounce up and down
Explanation:
Buoys are used for two main reasons, one is to let the people on land know of a big incoming wave, while the second reason is to generate electricity. When a big wave is approaching the buoy starts to bounce up and down with the strength of the smalled previous waves and then bounce very strongly up as the bigger wave passes by. This movement is combined with pistons within the buoy in order to conduct electricity.
Answer:
(b) the point charge is moved outside the sphere
Explanation:
Gauss' Law states that the electric flux of a closed surface is equal to the enclosed charge divided by permittivity of the medium.

According to this law, any charge outside the surface has no effect at all. Therefore (a) is not correct.
If the point charge is moved off the center, the points on the surface close to the charge will have higher flux and the points further away from the charge will have lesser flux. But as a result, the total flux will not change, because the enclosed charge is the same.
Therefore, (c) and (d) is not correct, because the enclosed charge is unchanged.