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melamori03 [73]
3 years ago
9

If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a

Physics
2 answers:
Lilit [14]3 years ago
7 0
If a molecule is found to have four hybrid sp3 then we say that it has a <span>tetrahedral molecular geometry. thsi is the correct term to define this type of molecules. So your option would be C. Hope this is useful</span>
diamong [38]3 years ago
3 0

Answer:

C is wrong, the correct answer is D

Explanation:

I just took the test

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electricity flows back and forth in an lc circuit with a .33 f capacitor and a .1 h inductor. what is the angular frequency and
Shalnov [3]

The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T. The formula for the angular frequency is = 2/T.

<h3>How is G determined in oscillation?</h3>

Use a stopwatch to calculate the oscillation's time period T. Calculate the pendulum's length L. Subtract the time period T's square from the length L.

<h3>How does oscillation's G work?</h3>

A mass attached to the end of a pendulum with a length of l causes it to oscillate with a period (T). T = 2(l/g), where g.

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4 0
1 year ago
Sound waves strike a glass and cause it to shatter.
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1. Resonance. Mechanical waves act on or through a medium, these waves can often have frequencies that are synchronized in a way that makes them act on the matter in the medium more "aggressively."
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3 years ago
Does a large object traveling slowly or a small object going fast have a greater momentum?
nekit [7.7K]

Answer:

It depends on the product of their mass and velocity

Explanation:

The momentum of a moving object is defined as the product of its mass and its moving velocity. So a same object would have larger momentum it's traveling faster, or gets heavier, and vice versa. In our case we don't have the exact value of speed and mass of both objects so we can't say which one has a greater momentum.

4 0
3 years ago
The parasailing system shown uses a winch to pull the rider in towards the boat, which is traveling with a constant velocity. Du
leonid [27]

Answer:

The magnitude of the force is  F_{net}= 1.837 *10^4N

the direction is 57.98° from the horizontal plane in a counter clockwise direction

Explanation:

From the question we are told that

      At t = 0 , \theta = 20^o

      The rate at which the angle increases is w = 2 \ ^o/s

Converting this to revolution per second  \theta ' = 2 \ ^o/s * \frac{\pi}{180} =0.0349\ rps

     The length  of the rope is defined by

                      r = 125- \frac{1}{3}t^{\frac{3}{2} }    

    At \theta  =30^o , The tension on the rope T = 18 kN

      Mass of the para-sailor is M_p = 75kg

Looking at the question we see that we can also denote the equation by which the length is defied as an an equation that define the linear displacement

  Now the derivative of displacement is velocity

   So

           r' = -\frac{1}{3} [\frac{3}{2} ] t^{\frac{1}{2} }

represents the velocity, again the derivative of velocity gives us acceleration

So

         r'' = -\frac{1}{4} t^{-\frac{1}{2} }

Now to the time when the rope made angle of 30° with the water

      generally angular velocity is mathematically represented as

                      w = \frac{\Delta \theta}{\Delta t}

Where \theta is the angular displacement

      Now considering the interval between 20^o \ to \ 30^o we have

                 2 = \frac{30 -20 }{t -0}

making t the subject

             t = \frac{10}{2}

               = 5s

Now at this time the displacement is

             r = 125- \frac{1}{3}(5)^{\frac{3}{2} }  

                = 121.273 m

The linear velocity is

             r' = -\frac{1}{3} [\frac{3}{2} ] (5)^{\frac{1}{2} }

                = -1.118 m/s

The linear acceleration is

          r'' = -\frac{1}{4} (5)^{-\frac{1}{2} }

              = -0.112m/s^2

Generally radial acceleration is mathematically represented by

         \alpha _R = r'' -r \theta'^2

              = -0.112 - (121.273)[0.0349]^2

              = 0.271 m/s^2

Generally angular acceleration  is mathematically represented by

                 \alpha_t = r \theta'' + 2 r' \theta '

Now \theta '' = \frac{d (0.0349)}{dt}  = 0

So

             \alpha _t = 121.273 * 0  + 2 * (-1.118)(0.0349)

                   = -0.07805 m/s^2

The net resultant  acceleration is mathematically represented as

                a = \sqrt{\alpha_R^2 + \alpha_t^2  }

                  = \sqrt{(-0.07805)^2  +(-0.027)^2}

                  = 0.272 m/s^2

Now the direction of the is acceleration is mathematically represented as

                  tan \theta_a = \frac{\alpha_R }{\alpha_t }

                       \theta_a = tan^{-1} \frac{-0.271}{-0.07805}

                           = 73.26^o

               

The force on the para-sailor along y-axis is mathematically represented as

               F_y = mg + Tsin 30^o + ma sin(90- \theta )

                    = (75 * 9.8) + (18 *10^3) sin 30 + (75 * 0.272)sin(90-73.26)

                    = 9.74*10^3 N

The force on the para-sailor along x-axis is mathematically represented as

              F_x = mg + Tcos 30^o + ma cos(90- \theta )    

             = (75 * 9.8) + (18 *10^3) cos 30 + (75 * 0.272)cos(90-73.26)

             = 1.557 *10^4 N

The net resultant force is mathematically evaluated as

                      F_{net} = \sqrt{F_x^2 + F_y^2}

                             =\sqrt{(1.557 *10^4)^2  + (9.74*10^3)^2}

                            F_{net}= 1.837 *10^4N

The direction of the force is

              tan \theta_f = \frac{F_y}{F_x}

                   \theta_f = tan^{-1} [\frac{1.557*10^4}{9.74*10^3} ]

                       = tan^{-1} (1.599)

                       = 57.98^o

     

                     

7 0
3 years ago
Which of the following is the princlple that all geologic processesd have occurred in the same manner today as they have always
Anvisha [2.4K]
I believe that is uniformitarianism :)
3 0
3 years ago
Read 2 more answers
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