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I understand here "bias" to be the uncertainty of measurements. So the order will be the following:
6.4 ± 0.5 s
<span>6.6 ± 0.1 s,
</span><span>6.63 ± 0.01 s,
</span><span>6.52 ± 0.05 s,
</span>
(notice how the second number, the one behind the symbol ± gets smaller, as the bias gets smaller).
The mass of the balloon decreases as the release of hydrogen gas.
<h3>Mass of hydrogen and percent change</h3>
If the balloon had expanded more then the mass of hydrogen gas will increase inside the balloon but the mass of the balloon decreasing because the hydrogen gas escape from the system means from the balloon.
There is less percent change in the mass of the balloon while on the other hand, the concentration of hydrogen gas increases inside the balloon which leads to expansion of balloon so we can conclude that the mass of the balloon decreases as the release of hydrogen gas.
Learn more about hydrogen here: brainly.com/question/19813237
Answer:
There were originally 8 atoms of Potassium-40.
Explanation:
The half-life of a radioactive material is the time taken for half the original material to decay or the time required for a quantity of the radioactive substance to reduce to half of its initial value.
If the original material formed without any Argon-40, it means that the atoms originally present were Potassium-40 atoms.
Presently, there are 7 Argon-40 atoms for every 1 of Potassium-40, we can deduce the number of half-lifes the Potassium-40 has undergone as follows :
After one half-life, (1/2) there will be one Potassium-40 atom for every Argon-40 atom.
After a second half life, 1/2 × 1/2 = 1/4: there will be one Potassium-40 atom for every three atoms of Argon-40.
After a third half-life, 1/4 × 1/2 = 1/8: there will be one Potassium-40 atom for every 7 atoms of Argon-40.
Since there are 1/8 atoms of Potassium-40 presently, there were originally 8 atoms of Potassium-40.
Answer:
The new pressure is 456.76 mmHg
Explanation:
Step 1: Data given
The initial volume of the gas = 5.80 L
The initial pressure of the gas = 1.00 atm
The volume of the gas increases to 9.65 L
The temperature is kept constant
Step 2: Calculate the new pressure
P1*V1 = P2¨V2
⇒with P1 = the initial pressure of the gas = 1.00 atm
⇒with V1 = the initial volume of the gas = 5.80 L
⇒with P2 = the new pressure = TO BE DETERMINED
⇒with V2 = the increased volume of the gas = 9.65 L
1.00 atm * 5.80 L = P2 * 9.65 L
P2 = (5.80 / 9.65)
P2 = 0.6010 atm
Step 3: Convert pressure from atm to mm Hg
0.6010 atm * 760 mmHg = 456.76 mmHg
The new pressure is 456.76 mmHg