Kepler's 3rd law is given as
P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant
Given:
P = 687 days
A = 1.52 AU
Therefore
k = P²/A³ = 687²/1.52³ = 1.3439 x 10⁵ days²/AU³
Answer: 1.3439 x 10⁵ (days²/AU³)
Answer:
lol im pretty sure pipes and nice pic of lil darkie
Explanation:
2+2=4
Answer:
i think u times them im not sure but then divide
Explanation:
To solve this problem, it would be helpful to know the density of 1 block
Density is defined as the mass of the substance per volume.
From the example given,
The density of the block is (7g)/(15.625 units^3) or 0.448 g/units^3.
So, if a block is added, the new mass is 7g + 7g = 14 g
And the volume 14 g /(density) = 1 unit^3