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Margarita [4]
3 years ago
10

Read the scenario below and answer the question that follows. Jane is a psychologist. She submits a study on sleep to a prestigi

ous journal, and the journal publishes the study. Later, Jane notices that the study has a serious flaw, which makes her results meaningless. Select the option in which Jane acts ethically. A. Jane submits a correction and retraction to the journal. B. Jane defends her work, even though she knows it is flawed. C. Jane ignores the flaw and does not respond to criticisms. D. Jane submits the paper to other journals quickly.
Physics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

A. Jane submits a correction and retraction to the journal

Explanation:

People submit their study to a journal in order to validate their work from their peers and further the field in which they are in.

Jane would have submitted her work believing that her work was flawless and correct. But later she realizes that she had made a mistake in her work. There are two ways in which she can act.

One way is to not be concerned with the fact that her study is flawed. This may lead to the rejection of her work by her peers and be detremental to her reputation.

Another way is to take responsibility and submit her corrected work which would lead to the publication of an accurate study. This would further her field also. This way is the right course of action.

Setler79 [48]3 years ago
3 0
A:the other options are examples of unethical behavior
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Ne4ueva [31]

Answer:

a) 0.159

b) 0.84

Explanation:

The Horizontal component is 2.3 times the vertical component

Let the horizontal electric field component = E_{h}

Let the vertical electric field component = E_{v}

The formula for light intensity is given by:

I = \frac{E_{m} ^{2} }{2c \mu}..............................(1)

E_{m} is the resolution of the vertical and horizontal components, E_{h} and    E_{v}

E_{m} ^{2} = E_{h} ^{2} + E_{v} ^{2}..................(2)

Light intensity before the glasses were put on:

I_{1}  = \frac{E_{m} ^{2} }{2c \mu_{1} }.............................(3)

Put equation (2) into equation (3)

I_{1}  = \frac{E_{h} ^{2} + E_{v} ^{2}}{2c \mu_{1} }.............................(4)

After the glasses were put on the horizontal component vanishes, i.e. E_{h} = 0

I_{2}  = \frac{ E_{v} ^{2}}{2c \mu_{2} }...................................(5)

Divide equation (5) by equation (4)

\frac{I_{2} }{I_{1} } = \frac{E_{v} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}...............................(6)

But E_{h} = 2.3E_{v}......................(7)

Insert equation (7) into (6)

\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2}  }{(2.3E_{v})^{2}   + E_{v} ^{2}   } \\\frac{I_{2} }{I_{1} } =  \frac{E_{v}^{2}  }{5.29E_{v}^{2}   + E_{v} ^{2}   }\\\frac{I_{2} }{I_{1} } =  \frac{E_{v}^{2}  }{6.29E_{v}^{2}  }\\\frac{I_{2} }{I_{1} } =\frac{1}{6.29} \\

\frac{I_{2} }{I_{1} }= 0.159

b) When the sunbather lies on his side, the vertical component vanishes, i.e E_{v} = 0

\frac{I_{2} }{I_{1} } = \frac{E_{h} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}

\frac{I_{2} }{I_{1} } = \frac{(2.3E_{v} )^{2}  }{E_{v} ^{2} +(2.3E_{v} )^{2}}

\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2}  }{E_{v} ^{2} +5.29E_{v}^{2} }

\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2}  }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } = \frac{5.29}{6.29} \\\frac{I_{2} }{I_{1} } = 0.84

8 0
3 years ago
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