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4 years ago

(a) Calculate the buoyant force on a 2.00-L helium balloon.

Physics

1 answer:

iragen [17]4 years ago

6 0

Answer:

0.0239364 N

0.0057879 N

Explanation:

$\rho$ = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

$F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N$

The buoyant force is 0.0239364 N

Net vertical force is given by

$F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N$

The net vertical force is 0.0057879 N

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What is created when charged particles are moving in a single direction and path?

photoshop1234 [79]

I think it is Drift Velocity.

4 0

3 years ago

Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t

lorasvet [3.4K]

Answer:

$V_3\approx 4.28\,\,V$

$I_1=0.0572\,\,amps$

$I_3\approx 0.171\,\,amps$

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

$\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega$

By knowing this, we can estimate the total current through the circuit,:

$Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps$

So approximately 0.17 amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

$V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V$

So now we know that the potential drop across the parellel resistors must be:

10 V - 4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

$I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps$

4 0

4 years ago

*R3= 9 ohms <br><br> What is the voltage drop running through resistor five?

joja [24]

The correct answer is: The voltage drop across $R_5$ is 45V.

Explanation:
First you need to find the total current of the circuit, which is:
According to Ohm's law:

V = I * R

I = V/R --- (1)

Where
R = Total Equivalent resistance of the circuit
V = Total Voltage = 90V
I -= Total Current

First let us find the equivalent resistance:
$R = R_1 + R_2 + R_5 + \frac{R_3*R_4}{R_3+R_4} \\
R = 3 + 6 + 15 + \frac{9*18}{9+18} \\
R = 30$

Now plug in the values in (1):
(1) => I = 90/30 = 3A

Now that we have current of the circuit, we can now find the voltage drop across $R_5$ = 15 ohms using:
$V_5 = I * R_5$

Where $V_5$ is the voltage drop across resistor 5;
$V_5 = 3 * 15 = 45V$

5 0

3 years ago

How does the process of convection within the earth drive the creation of various earth features?

Nookie1986 [14]

Answer:

The process is a mechanism known as mantle convection

Explanation:

Mantle convection is the driving mechanism for plate tectonics, which is the process ultimately responsible for producing earthquakes, mountain ranges, and volcanos on Earth.

This mechanism occurs in four different patterns

Collision: this is the shoving together of two continental plates

Subduction: this is the plunging of one plate beneath another

Spreading: this is the pushing apart of two plates
Transform faulting: this occurs when two plates slide past each other

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3 years ago

Which is not a common theory on how the effects of hypnosis occurs

olasank [31]

Answer:

EFFECTS Adverse reactions to hypnosis are rare, but may include: Headache. Drowsiness. Dizziness

6 0

3 years ago