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dmitriy555 [2]
3 years ago
13

Which conclusion, based on measurements of the ball in the lab in this lesson, is correct? a. The density of the ball was 1.48 g

/cm3, so it was made of synthetic or manufactured rubber. b. The density of the ball was 1.23 g/cm3, so it was made of Neoprene rubber. c. The density of the ball was 1.48 g/cm3, so it was made of natural rubber. d. The density of the ball was 0.90 g/cm3, so it was made of gum rubber.
Physics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

u dummy

Explanation:

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Answer:

Option B. 3.0×10¯¹¹ F.

Explanation:

The following data were obtained from the question:

Potential difference (V) = 100 V.

Charge (Q) = 3.0×10¯⁹ C.

Capacitance (C) =..?

The capacitance, C of a capacitor is simply defined as the ratio of charge, Q on either plates to the potential difference, V between them. Mathematically, it is expressed as:

Capacitance (C) = Charge (Q) / Potential difference (V)

C = Q/V

With the above formula, we can obtain the capacitance of the parallel plate capacitor as follow:

Potential difference (V) = 100 V.

Charge (Q) = 3.0×10¯⁹ C.

Capacitance (C) =..?

C = Q/V

C = 3.0×10¯⁹ / 100

C = 3.0×10¯¹¹ F.

Therefore, the capacitance of the parallel plate capacitor is 3.0×10¯¹¹ F.

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