The displacement is the area under the graphs. C is 5x2=10m and D is 0.5 x 2.5 x 2.5 = 6.25m
Answer:
Y = 31750 Pa = 31.75 KPa (For 24.5 N force)
Y = 312500 Pa = 312.5 KPa (For 250 N force)
Explanation:
Since the elongation is constant. Therefore, the strain will remain the same in both cases:
<u>FOR A FORCE OF 25.4 N</u>:
Now, for Young's Modulus:
<u>Y = 31750 Pa = 31.75 KPa</u>
<u></u>
<u>FOR A FORCE OF 520 N</u>:
Now, for Young's Modulus:
<u>Y = 312500 Pa = 312.5 KPa</u>
Answer:
In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.