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3 years ago

A wire is carrying current vertically downward. What is the direction of the force due to Earth's magnetic field on the wire?

Physics

1 answer:

AnnyKZ [126]3 years ago

6 0

Answer:

The direction of the force will be towards the east

Explanation:

From the question we are told that

The direction of the downward

Generally according to Fleming's right-hand rule(

Thumb - direction of force

Middle finger - direction of current

Index finger - direction of the magnetic field

) and the fact that the earth magnetic field acts from south to north with respect to the four cardinal points then the direction of the force will be toward the east with respect to the four cardinal point on the earth

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The rare earth elements include

irga5000 [103]

~Hello there!

Your questions: The rare Earth elements include ___________________.

Your answer: There are many Earth elements but some of the rare elements are the following as mentioned:

1) Gadolinium

2) Holmium

3) Yttrium

4) Promethium

5) Samarium.

Note: These are some of the rare Earth elements, there are MANY rare elements that are found in Earth.

Any questions ^?

Happy Studying!

7 0

3 years ago

Whay is the other name of negative acceleration.

sladkih [1.3K]

Answer:

deceleration? I think because the prefix de means to like not or to slow down

8 0

3 years ago

Two equally charged, 2.807 g spheres are placed with 3.711 cm between their centers. When released, each begins to accelerate at

statuscvo [17]

$\begin{gathered} m=\text{ 2.807 g} \\ d=\text{ 3.711cm} \\ a=260.125\text{ m/s}^2 \\ m=\text{ mass of both the spheres} \\ d=\text{ distance between the centers of sphere.} \\ a=\text{ acceleration of spheres.} \end{gathered}$ $\begin{gathered} force\text{ due to the sphere having charge q, outside its surface is given by } \\ \vec{F}=\frac{1}{4\pi\epsilon_o}\frac{q_1q_2}{r^2}\hat{r} \\ q_1=charge\text{ on the source object.} \\ q_2=charge\text{ of the object in which we are observing the force.} \\ F=\text{ the force on the charged particle outside the sphere} \\ r=\text{ distance of the charged particle from the center of the sphere} \\ \hat{r}\text{= direction of the force acting on the charged particle} \end{gathered}$ $\begin{gathered} from\text{ Newton's second law} \\ F=ma \\ F=\text{ force acting on the particle.} \\ m=\text{ mass of the object.} \\ a=\text{ acceleration of the object.} \end{gathered}$ $\begin{gathered} from\text{ both the equation } \\ ma=\frac{1}{4\pi\epsilon_o}\frac{q_1q_{\frac{2}{}}}{r^2}\hat{r} \\ here\text{ q}_1\text{ and q}_2\text{ are the same, according to the question.} \end{gathered}$ $\begin{gathered} converting\text{ all the values in s.i. unit} \\ m=2.807*10^{-3}kg \\ d=3.711*10^{-2}m \\ according\text{ to the question q}_1=\text{ q}_2 \\ value\text{ of }\frac{1}{4\pi\epsilon_o}=9*10^9\text{ Nm}^2\text{/C}^2 \\ now\text{ put all the values in the above equation } \\ 2.807*10^{-3}kg*260.125\text{ m/s\textasciicircum2}=9*10^9Nm^2\text{/C}^2*\frac{q^2}{3.711*10^{-2}m} \\ \end{gathered}$ $\begin{gathered} by\text{ trasformation} \\ q=\sqrt{\frac{2.807*10^{-3}kg*260.125m/s^2*3.711*^10^{-2}m}{9*10^9Nm^2\text{/C}^2}} \\ by\text{ solving this we get } \\ q=17.3514*10^{-7}C \\ q=1.73514\text{ micro coulombs.} \end{gathered}$ Hence the correct answer is q= 1.73514 micro coulombs.

5 0

1 year ago

If vector A=2i+3j-k and vector B=4i+6j-2k. The angle between them will be: a) 0°b)45°c)90°d)60°

melomori [17]

Notice that

B = 4i + 6j - 2k = 2 (2i + 3j - k) = 2A

so both vectors point in the same direction and the angle between them is (A) 0°.

7 0

3 years ago

Convertir en utilisant les puissances de 10

kirza4 [7]

Explanation:

Bonjour , pourriez-vous m'aider à faire cet exercice svp ??

a) Convertir les longueurs suivantes en utilisant les puissances de 10.

1,7 cm en mètre

0,48 km en mètre

49 mm en mètre

35 m en centimètre

63 km en mètre

568 Mm en kilomètre

b) Ecrire les longueurs ainsi converties en utilisant la notation scientifique

4 0

3 years ago