Please help answer much as possible there's 4 questions
2 answers:
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Answer:
The magnitude of the free-fall acceleration at the orbit of the Moon is (
, where
).
Explanation:
According to the Newton's Law of Gravitation, free fall acceleration (), in meters per square second, is directly proportional to the mass of the Earth (
), in kilograms, and inversely proportional to the distance from the center of the Earth (
), in meters:
(1)
Where:
- Gravitational constant, in cubic meters per kilogram-square second.
- Mass of the Earth, in kilograms.
- Distance from the center of the Earth, in meters.
If we know that ,
and
, then the free-fall acceleration at the orbit of the Moon is:
Answer:
E) d/sqrt2
Explanation:
The initial electric force between the two charge is given by:
where
k is the Coulomb's constant
q1, q2 are the two charges
d is the separation between the two charges
We can also rewrite it as
So if we want to make the force F twice as strong,
F' = 2F
the new distance between the charges would be
so the correct option is E.