Question

Claudia goes bungee jumping. She has a mass of 51 kg.

Answer 1

a) According to Hooke's law:

k=F/m=40 N/m.

b) x=mg/k=12.5 m

c) x=F.max/k=375 m.

Answer 2

Here Bungee will behave like an ideal spring

PART A)

so we know that spring force is given as

$F = kx$

here we know that

F = 200 N

x = 5 m

now from above equation

$200 = k (5)$

$k = 40 N/m$

PART b)

As we know that mass of the Claudia = 51 kg

now its force due to weight is given as

$F = mg$

$F = 51(9.8) = 499.8 N$

now from the above formula of spring

$F = kx$

$499.8 = 40(x)$

$x = 12.5 m$

so bungee will be stretch by 12.5 m distance

Part C)

Maximum force on the bungee is given as

$F = kx$

$F = 15000 N$

$15000 = 40 x$

$x = 375 m$

so it will stretch by 375 m distance