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Rudik [331]
3 years ago
6

What causes the sea floor to move apart at a sea floor spreading center A density B continental drift C paleomagnetism D convect

ion currents
Chemistry
1 answer:
pochemuha3 years ago
8 0

Answer: D convection currents

Explanation:

The seafloor spreading is a phenomena that occurs due to liberation of heat from the convection currents generated in the mantle. It makes the earth crust more plastic and less dense. This happens at divergent plate boundaries. As the plates move apart, the less denser material rises. It leads to the formation of mountain and crust cracks.

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How many decigrams are in 4.6 decagrams?
11111nata11111 [884]

Answer:

\large \boxed{\text{460 dg}}

Explanation:

1. Convert decagrams to grams

\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}

2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

3 0
3 years ago
Read 2 more answers
The vapor pressure of ethanol at
Karo-lina-s [1.5K]
482VP I think is  the correct answer.
5 0
3 years ago
Which one would it be since covalent bond is not here :( please help meeee
timurjin [86]
Non polar covalent bond. The Cl's electronegativity is the same since it's the same atom. Therefore, they will be nonpolar
5 0
3 years ago
Would it be C???...idk<br> HELP
givi [52]

Answer:

C.  Butanal , is the aldehyde

Explanation:

A . It is carboxylic acid : ---COOH group

B. It is Ester : ----COOR group , Here R = CH3

C. It is Aldehyde : -----CHO group

D. It is ketone : ----C=O group

See image :

8 0
3 years ago
How many grams of methane gas (CH4) need to be combusted to produce 12.5 L water vapor at 301 K and 1.1 atm? Show all of the wor
tangare [24]
Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V = n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm · 12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.
4 0
3 years ago
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