Answercan you upload the pictures??
Explanation:
Answer:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Explanation:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.
2KHCO3+ H3PO4 arrow K2HPO4 + H20 + C02
Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + C02
There are 2 carbons on the left. You need 2 on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + 2C02
That should do it.
Let's make a table to show balance.
Species K H C PO4- O
Left 2 5 2 1 6 from CO3^(2-)
Right 2 5 2 1 6 from H2O/CO2
Answer:
Explanation:
Given:
Ka of HClO2 = 1.1 × 10-2
Ka of HCHO2 = 1.8 × 10-4
Ka of HCN = 4.9 × 10-10
Ka of HNO2 = 4.6 × 10-4
Ka of HF = 3.5 × 10-4
All at a concentration of 0.1 M
A.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HClO2] = 0.1 M
HClO2 --> ClO2^- + H+
1.1 × 10-2 = x^2/0.1
x = sqrt(1.1 × 10^-3
= 0.033 M
pH = -log[H+]
= 1.48
B.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HCHO2] = 0.1 M
HCHO2 --> CHO2^- + H+
1.8 × 10-4 = x^2/0.1
x = sqrt(1.8 × 10^-5)
= 0.0042 M
pH = -log[H+]
= 2.37
C.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HCN] = 0.1 M
HCN --> CN- + H+
4.9 × 10-10 = x^2/0.1
x = sqrt(4.9 × 10-11)
= 0.000007 M
pH = -log[H+]
= 5.16
D.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HNO2] = 0.1 M
HNO2 --> NO2^- + H+
4.6 × 10-4 = x^2/0.1
x = sqrt(4.6 × 10-5)
= 0.0068 M
pH = -log[H+]
= 2.17
E.
HA --> H+ + A-
Ka = [H+] × [A-]/[HA]
[H+] = [A-] = x
[HF] = 0.1 M
HF --> F- + H+
3.5 × 10-4 = x^2/0.1
x = sqrt(3.5 × 10-5)
= 0.0059 M
pH = -log[H+]
= 2.23
a) pH = 1.48
b) pH = 2.37
c) pH = 5.16
d) pH = 2.17
e) pH = 2.33
HCN is most basic because;
smallest Ka
Highest pH value = 5.16
Explanation:
It is known that relation between wavelength and frequency is as follows.
where, 
= wavelength
c = speed of light = 
[/tex]\nu[/tex] = frequency
It is given that frequency is 
. Hence, putting this value into the above formula and calculate the wavelength as follows.
= 
or, = 
Thus, we can conclude that wavelength of given radiation is .
