**Answer:**

(a) Maximum height = 53.88 meters

(b) Range of the ball = 924.36 meters

**Explanation:**

The ball has been launched at a speed = 44.4 meters per second

Angle of the ball with the horizontal = 25°

Horizontal component of the speed of the ball = 44.4cos25° = 40.24 meters per second

Vertical component = 44.4sin25° = 18.76 meters per second

We know vertical component of the speed decides the height of the ball so by the law of motion,

v² = u² - 2gh

where v = velocity at the maximum height = 0

u = initial velocity = 18.76 meter per second

g = gravitational force = 9.8 meter per second²

Now we plug in the values in the given equation

0 = (18.76)² - 2(9.8)(h)

19.6h = 352.10

h =

h = 17.96 meters

By another equation,

Now we plug in the values again

18.76t = 4.9t²

18.76 = 4.9t

t = seconds

Since time t is the time to cover half of the range.

Therefore, time taken by the ball to cover the complete range = 2×3.83 = 7.66 seconds

So the range of the ball = Horizontal component of the velocity × time

= 40.24 × 7.66

= 308.12 meters

This we have calculated all for our planet.

Now we take other planet.

**(a)** Since the golfer drives the ball 3 times as far as he would have on earth then **maximum height achieved by the ball** = 17.96 × 3 = **53.88 meters**

**(b)** **Range** of the ball = 3×308.12 = **924.36 meters**