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Mila [183]
3 years ago
5

Match these items.

Physics
1 answer:
horrorfan [7]3 years ago
4 0
Iron oxide = small region within a magnet
drop or hammer =man-made magnet
strength decreases rapidly with distance lines of force
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If the current through a resistor is 12 A and the voltage drop is 12 V, what is the power absorbed by the resistor? Answer to th
klasskru [66]

Answer:

144 W

Explanation:

The power absorbed by a resistor is the product of the current passing through it and the voltage drop across it. Hence

P=IV

P=12\text{ A}\times12\text{ V}=144 \text{ W}

Other variations of this formula are derived using Ohm's law, V=IR

P=I^2R=\dfrac{V^2}{R}

R is the resistance of the resistor. It is what causes the voltage drop.

7 0
3 years ago
A rigid container holds 0.30g of hydrogen gas.
Strike441 [17]

Answer:

Part A:    \mathbf{Q =94 \ J} to two significant figures

Part B:    \mathbf{Q =160  \ J} to two significant figures

Part C:    \mathbf{Q =220  \ J} to two significant figures

Explanation:

Given that :

mass of the hydrogen = 0.30 g

the molar mass of hydrogen gas molecule = 2 g/mol

we all know that:

number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol

number of moles = 0.15 mol

For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = C_v=\dfrac{3}{2}R

For Part A:

Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{3}{2})(8.314 \ J/mole.K )(100-50)K

Q= 0.15 \times (\dfrac{3}{2}) \times (8.314 \ J )\times (50)

Q=93.5325 \ J

\mathbf{Q =94 \ J} to two significant figures

Part B. For hot temperature, C_v=\dfrac{5}{2}R

Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{5}{2})(8.314 \ J/mole.K )(300-250)K

Q= 0.15 \times (\dfrac{5}{2}) \times (8.314 \ J )\times (50)

Q=155.8875 \ J

\mathbf{Q =160  \ J} to two significant figures

Part C. For an extremely hot temperature, C_v=\dfrac{7}{2}R

Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{7}{2})(8.314 \ J/mole.K )(2300-2250)K

Q= 0.15 \times (\dfrac{7}{2}) \times (8.314 \ J )\times (50)

Q=218.2425 \ J

\mathbf{Q =220  \ J} to two significant figures

6 0
3 years ago
Which type of bone is this <br>covalent bond<br>hydrogen bond <br>ionic bond​
Fynjy0 [20]

Answer:

Explanation:A covalent bond is formed when electrons are shared between non-metal atoms, and the positive nuclei are attracted towards the pair of negative bonded electrons. ... Hence, the hydrogen bond is weaker than ionic and covalent bonds. Example: Water molecules are held to each other by intermolecular forces of attraction.

5 0
3 years ago
An observer on Earth sees rocket 1 leave Earth and travel toward Planet X at 0.3c. The observer on Earth also sees that Planet X
Verizon [17]

Answer:

0.625 c

Explanation:

Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.

In the context,

The relative speed of body 2 with respect to body 1 can be expressed as :

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

Speed of rocket 1 with respect to rocket 2 :

$u' = \frac{0.4 c- (-0.3 c)}{1-\frac{(0.4 c)(-0.3 c)}{c^2}}$

$u' = \frac{0.7 c}{1.12}$

u'=0.625 c

Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c

5 0
3 years ago
Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
umka2103 [35]

Answer:

a) F=2.048\times 10^{-7}\ N

b) a=0.1138\ m.s^{-2}

Explanation:

Given:

  • mass of raindrops, m=1.8\times 10^{-6}\ kg
  • charge on the raindrops, q=+21\times 10^{-12}\ C
  • horizontal distance between the raindrops, r=0.0044\ m

A)

<u>From the Coulomb's Law the force between the charges is given as:</u>

F=\frac{1}{4\pi.\epsilon_0} .\frac{q_1.q_2}{r^2}

we have:

\epsilon_0=8.854\times 10^{-12}\ C^2.N^{-1}.m^{-2}

<em>Now force:</em>

F=\frac{1}{4\pi\times 8.854\times 10^{-12}} .\frac{21\times 10^{-12}\times 21\times 10^{-12}}{0.0044^2}

F=2.048\times 10^{-7}\ N

B)

<u>Now the acceleration on the raindrops due to the electrostatic force:</u>

a=\frac{F}{m}

a=\frac{2.048\times 10^{-7}}{1.8\times 10^{-6}}

a=0.1138\ m.s^{-2}

7 0
3 years ago
Read 2 more answers
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