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Alex777 [14]
3 years ago
9

State one difference between solar cells and solar heating systems?

Physics
2 answers:
steposvetlana [31]3 years ago
6 0
In a residential solar thermal system, called the Solar Heating System, the solar panels are of the Solar Thermal Collector type, which have the function of capturing the thermal energy of the solar radiation and transferring it to the water, heating it.
This water will be stored in a thermal reservoir, which will maintain its temperature until the moment of use.
The size of the reservoir and the area of solar thermal collectors (solar heating plates) required for the solar heating system vary according to the amount of hot water used in the residence.
This is simple to calculate after an interview with the residents, where the consumption profile will be studied according to the habits of bathing, washing utensils, clothes, etc.


In a residential solar photovoltaic generator system the solar panels are of the photovoltaic module type, consisting of photovoltaic solar cells that transform solar radiation into direct current electric energy.
For the operation of an on-grid photovoltaic solar system (connected to the grid) it is necessary to use a grid-tie inverter, which converts the energy generated into continuous currents by the photovoltaic solar panels into current electric energy Alternating.
The grid-tie inverter is then connected to the general picture of the residence, where it is in charge of mixing the solar energy (already in alternating current) with the power of the public network, allowing to use it in any apparatus or electrical equipment.
seropon [69]3 years ago
4 0
Solar photovoltaic cells, or solar panels, are arrays of silicon cells that can transforms light radiation into electricity. Solar heating system absorbs the heat from the sun and either transform it into electricity through s generator or uses the energy to heat homes and water.
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If are spaced closely together on the map,there is a drastic temperature change over the distance
AlexFokin [52]

If <em>the isotherms</em> are spaced closely together over some portion of the map, there is a drastic temperature change over that portion.

6 0
3 years ago
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A 4.44 l container holds 15.4 g of oxygen at 22.55°c. what is the pressure?
padilas [110]
We will use the ideal gas equation:
PV = nRT, where n is moles and equal to mass / Mr
P = mRT/MrV
P = 15.4 x 8.314 x (22.55 + 273) / 32 x 4.44
P = 266.3 kPa
5 0
3 years ago
4. Una cuerda de acero de piano mide 1.60 m de longitud y 0.20 cm de diámetro. ¿Cuál es la tensión en la cuerda si se estira 0.2
bazaltina [42]

Answer:

1030.83\ \text{N}

Explanation:

\Delta L = Cambio en la longitud de la cuerda = 0.25 cm

T = tensión en cuerda

A = Área de la cadena = \dfrac{\pi}{4}d^2

d = Diámetro de la cuerda = 0.2 cm

L = Longitud original de la cuerda = 1.6 m

El cambio de longitud de una cuerda viene dado por

\Delta L=\dfrac{TL}{AE}\\\Rightarrow T=\dfrac{\Delta LAE}{L}\\\Rightarrow T=\dfrac{0.25\times 10^{-2}\times \dfrac{\pi}{4}(0.2\times 10^{-2})^2\times 210\times 10^9}{1.6}\\\Rightarrow T=1030.84\ \text{N}

La tensión en la cuerda es 1030.84\ \text{N}.

8 0
2 years ago
A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhauste
marusya05 [52]

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (Q_{out}), in megawatts:

Q_{out} = Q_{in} - W

Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W(1)

Where:

  • \eta - Efficiency.
  • W - Electric power, in megawatts.

If we know that \eta = 0.39 and W = 330\,MW, then the energy rate exhausted to the river is:

Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)

Q_{out} = 516.154\,MW

516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473

7 0
3 years ago
A force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s^2. If a force of 5 newtons is applied to a mass o
nignag [31]

For any force and any mass, the acceleration is always

(the strength of the force) divided by (the mass) .

If a force of 5 newtons is applied to a mass of 5 kg, the acceleration will be

(5 Newtons) / (5 kg) = <em>1 m/s²</em>

7 0
3 years ago
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