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Alex777 [14]
3 years ago
9

State one difference between solar cells and solar heating systems?

Physics
2 answers:
steposvetlana [31]3 years ago
6 0
In a residential solar thermal system, called the Solar Heating System, the solar panels are of the Solar Thermal Collector type, which have the function of capturing the thermal energy of the solar radiation and transferring it to the water, heating it.
This water will be stored in a thermal reservoir, which will maintain its temperature until the moment of use.
The size of the reservoir and the area of solar thermal collectors (solar heating plates) required for the solar heating system vary according to the amount of hot water used in the residence.
This is simple to calculate after an interview with the residents, where the consumption profile will be studied according to the habits of bathing, washing utensils, clothes, etc.


In a residential solar photovoltaic generator system the solar panels are of the photovoltaic module type, consisting of photovoltaic solar cells that transform solar radiation into direct current electric energy.
For the operation of an on-grid photovoltaic solar system (connected to the grid) it is necessary to use a grid-tie inverter, which converts the energy generated into continuous currents by the photovoltaic solar panels into current electric energy Alternating.
The grid-tie inverter is then connected to the general picture of the residence, where it is in charge of mixing the solar energy (already in alternating current) with the power of the public network, allowing to use it in any apparatus or electrical equipment.
seropon [69]3 years ago
4 0
Solar photovoltaic cells, or solar panels, are arrays of silicon cells that can transforms light radiation into electricity. Solar heating system absorbs the heat from the sun and either transform it into electricity through s generator or uses the energy to heat homes and water.
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A car transports its passengers between 3 buildings. It moves from the first building to the second building, 4.76km away, in a
BigorU [14]

Answer:

1) a = 6.14 km

2) b = 4.69 km

Explanation:

Let the first building be A, second building be B and third building be C.

Now, bearing of A = 4.76 km in a direction 37° north of east

Bearing of B = 69° west of north

Bearing of C = 28° east of south

Thus if this 3 points form a triangle, we will have the following angles;

Angle at point A = 28 + (90 - 37) = 81°

Angle at point B = 28 + (90 - 69) = 49°

Angle at point C = 180 - (81 + 49) = 50°

Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;

Using sine rule, we can find "a".

a/sin 81 = 4.76/sin 50

a = 6.14 km

B) distance between first and third building is AB in the triangle depicted by "b".

Similar to the first problem, we will use sine rule again.

b/sin49 = 4.76/sin 50

b = 4.69 km

8 0
2 years ago
Darren drives to school in rush hour traffic and averages 28 mph. He returns home in mid-afternoon when there is less traffic an
Gala2k [10]

Answer:

distance between school and home is 21 miles

Explanation:

given data

in rush hour speed  s1 = 28 mph

less traffic speed s2 = 42 mph

time t = 1 hr 15 min = 1.25 hr

to find out

distance  d

solution

we consider here distance home to school is d and t1 time to reach at school

we get here distance equation when we go home to school that is

distance = 28 × t1    .......................1

and when we go school to home distance will be

distance = 42 × ( t - t1 )

distance = 42 × ( 1.25 - t1 )     ...................2

so from equation 1 and 2

28 × t1 = 42 × ( 1.25 - t1 )

t1 = 0.75

so

from equation 1

distance = 28 × t1

distance = 28 × 0.75

distance = 21 miles

4 0
3 years ago
a 8000kg tow truck pulls a 3000kg car horizontally into a garage. if the motor of the tow truck exerts a forward thrust on the t
Evgen [1.6K]
Equation 1 :
m1 :   m1a =T 
Equation 2:m2 : m2a= F - T 

Adding 1 and 2a=0.073

Placing in  equation 1

we get T = 218.18N
8 0
3 years ago
A solenoid has a radius Rs = 14.0 cm, length L = 3.50 m, and Ns = 6500 turns. The current in the solenoid decreases at the rate
babymother [125]

Answer:

E = 58.7 V/m

Explanation:

As we know that flux linked with the coil is given as

\phi = NBA

here we have

A = \pi R_s^2

B = \mu_o N i/L

now we have

\phi = N(\mu_o N i/L)(\pi R_s^2)

now the induced EMF is rate of change in magnetic flux

EMF = \frac{d\phi}{dt} = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

now for induced electric field in the coil is linked with the EMF as

\int E. dL = EMF

E(2\pi r_c) = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

E = \frac{\mu_o N^2 R_s^2 \frac{di}{dt}}{2 r_c L}

E = \frac{(4\pi \times 10^{-7})(6500^2)(0.14^2)(79)}{2(0.20)(3.50)}

E = 58.7 V/m

3 0
3 years ago
1. A limiting factor for using nuclear energy is the
Goryan [66]

Answer:

waste

Explanation:

took da test. nhgvgg

8 0
3 years ago
Read 2 more answers
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