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Orlov [11]
3 years ago
8

A small model car with mass m travels at a constant speed on the inside of a track that is a vertical circle radius 5.00 m. If t

he normal force exerted by the track on the car when it is at the bottom of the track (point A) is equal to 2.50 mg, how much time does it take the car to complete one revolution around the track?
Physics
1 answer:
dolphi86 [110]3 years ago
6 0
One point to another
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The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 N. The canister initially has a
Effectus [21]

Answer:44.58 J

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mass of block \left ( m\right )=2.5 kg

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Initial velocity =2.3\hat{i} m/s

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4 0
3 years ago
What is its speed after 3. 83 as if it accelerates uniformly at −3. 04 m/s 2 ? answer in units of m/s.
weeeeeb [17]

The velocity equation is v_{final} =v_{initial} +at\\

Known facts:

  • t = 3.83s
  • a= -3.04
  • intial velocity = 0

Plug into equation known quantities:

   v_{final} = (-3.04) * 3.83 = -11.6432m/s

Thus the final velocity is -11.6432m/s

Hope that helps!

6 0
3 years ago
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