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Orlov [11]
3 years ago
8

A small model car with mass m travels at a constant speed on the inside of a track that is a vertical circle radius 5.00 m. If t

he normal force exerted by the track on the car when it is at the bottom of the track (point A) is equal to 2.50 mg, how much time does it take the car to complete one revolution around the track?
Physics
1 answer:
dolphi86 [110]3 years ago
6 0
One point to another
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With the flow of the water
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What are the three types of friction and when does each apply
Annette [7]
Sliding: when an object slides across a surface
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4 0
4 years ago
I place an ice cube with a mass of 0.223 kg and a temperature of −35◦C is placed into an insulated aluminum container with a mas
Nadya [2.5K]

To solve this problem it is necessary to use the calorimetry principle. From the statement it asks about the remaining ice, that is, to the point where the final temperature is 0 ° C.

We will calculate the melted ice and in the end we will subtract the total initial mass to find out how much mass was left.

The amount of heat transferred is defined by

Q = mc\Delta T

Where,

m = mass

c = Specific heat

\Delta T =Change in temperature

There are two states, the first is that of heat absorbed by that mass 'm' of melted ice and the second is that of heat absorbed by heat from -35 ° C until 0 ° C is reached.

Performing energy balance then we will have to

Q_i-E_h = Q_m

Where,

Q_ i= Heat absorbed by whole ice

Q_m= Heat absorbed by mass

E_h= Heat energy by latent heat fusion/melting

m_i*c_i \Delta T +m*L_f  = (m_wc_w+m_{al}c_{al})\Delta T

Replacing with our values we have that

0.223*2108(-(-35))+m*3.34*10^5 = (0.452*4186+0.553*902)(27-0)

16452.9+334000m = (1892.072+498.806)*27

Rearrange and find m,

m = 0.144Kg

Therefore the Ice left would be

m' = 0.223-0.144

m' = 0.079Kg

Therefore there is 0.079kg ice in the containter when it reaches equilibrium

8 0
4 years ago
A coil of wire has been wrapped into a circle of 100 times with a diameter of 2.0 m. The coil is placed in a magnetic field of 5
jek_recluse [69]

Answer:

1570 V

Explanation:

N = 100

diameter = 2 m

radius = 1 m

B = 5 tesla

initailly the angle between the area vector of the coil and the magnetic field is zero and then the angle becomes 180 degree.

t = 2 s

Let Φ be the initial magnetic flux.

Φ = B A Cos 0 = 5 x 3.14 x 1 x 1 x 1 = 15.7 Wb

Let Φ' be the final magnetic flux

Φ' = B A Cos 180 = - 5 x 3,14 x 1 x 1 x 1 = - 15.7 Wb

According to the law of electromagnetic induction, the induced emf developed is equal to the rate of change of magnetic flux linked with the coil.

e = -N\frac{d\phi }{dt}=\frac{\phi '-\phi }{t}

e =-100\frac{-15.7-15.7}{2}=1570 V

4 0
3 years ago
A student has to work the following problem: A block is being pulled along at constant speed on a horizontal surface a distance
brilliants [131]

Answer:

D

The answer cannot be found until it is known whether q is greater than, less than, or equal to 45°.

Explanation:

Since block moves with constant speed

So, frictional force

f = FCosq

Work done by friction

W = - fd

W = - fd Cos q

The answer may be greater or less than - fdSinq. It depends on the value of q which is less than, or equal to 45°.

6 0
3 years ago
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