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kogti [31]
3 years ago
8

What is the difference between natural and artificial transmutation? Give an example of each.

Chemistry
1 answer:
cricket20 [7]3 years ago
6 0

Explanation:

Natural transmutation is the spontaneous disintegration of a heavy nuclide into lighter ones or fusion of lighter nuclides into heavier ones. These processes occurs naturally without anything inducing them. Nuclear fission of light elements in the core of stars is an example of natural transmutation.

  • Typically, all nuclei with atomic number greater than 83 are naturally radioactive.

         ²³⁸₉₂U  →  ²³⁴₉₂Th  + ⁴₂He

In artificial transmutation,  nuclear reactions are initiated through the collision of a nuclide with a high speed particle. Here, unstable nuclei are produced artificially in nuclear reactions. Such unstable nuclei also produce radiations.

          ¹₀n  + ²³₁₁Na → ²⁴₁₁Na + γ

Learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

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The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.
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C: 0.012 mol.

<h3>Explanation</h3>

Start with 0.0020 moles of iodate ions {\text{IO}_{3}}^{-}.

How many moles of iodine \text{I}_2 will be produced?

{\text{IO}_{3}}^{-} converts to \text{I}_2 in the first reaction. The coefficient in front of \text{I}_2 is three times the coefficient in front of {\text{IO}_{3}}^{-}. In other words, each mole of {\text{IO}_{3}}^{-} will produce three moles of \text{I}_2. 0.0020 moles of {\text{IO}_{3}}^{-} will convert to 0.0060 moles of \text{I}_2.

How many moles of thiosulfate ions {\text{S}_2\text{O}_3}^{2-} are required?

\text{I}_2 reacts with {\text{S}_2\text{O}_3}^{2-} in the second reaction. The coefficient in front of \text{I}_2 is twice the coefficient in front of {\text{S}_2\text{O}_3}^{2-}. How many moles of {\text{S}_2\text{O}_3}^{2-} does each mole of \text{I}_2 consume? Two. 0.0060 moles of \text{I}_2 will be produced. As a result, 2 \times 0.0060 = 0.0120 moles of {\text{S}_2\text{O}_3}^{2-} will be needed.

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A chemist determined by measurements that 0.050 moles of aluminum participated in a chemical reaction. Calculate the mass of alu
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Answer:

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Explanation:

This question is solved easily if we remember that the number of moles is obtained by dividing the mass into the atomic weight or molar mass depending if we are referring to elements or molecules.

Therefore, the mass of aluminum in the reaction will the 0.050 mol Al times the atomic weight of aluminum.

number of moles = n = mass of Al / Atomic Weight Al

⇒ mass Al = n x Atomic Weight Al = 0.050 mol x 27 g mol⁻¹

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We have three significant figures in 0.050 and therefore we should have three significant figures in our answer.

           

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