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4 years ago

What is the difference between natural and artificial transmutation? Give an example of each.

Chemistry

1 answer:

cricket20 [7]4 years ago

6 0

Explanation:

Natural transmutation is the spontaneous disintegration of a heavy nuclide into lighter ones or fusion of lighter nuclides into heavier ones. These processes occurs naturally without anything inducing them. Nuclear fission of light elements in the core of stars is an example of natural transmutation.

Typically, all nuclei with atomic number greater than 83 are naturally radioactive.

²³⁸₉₂U → ²³⁴₉₂Th + ⁴₂He

In artificial transmutation, nuclear reactions are initiated through the collision of a nuclide with a high speed particle. Here, unstable nuclei are produced artificially in nuclear reactions. Such unstable nuclei also produce radiations.

¹₀n + ²³₁₁Na → ²⁴₁₁Na + γ

Learn more:

Transmutation brainly.com/question/3433940

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The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

Lera25 [3.4K]

The allowable combination for the atomic orbital is n=4, l=2, $m_{l}$ =2.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with $m_{l}$ =+2the l value must be higher than 1. There are two l values that are consistent with n and $m_{l}$ values: l= 2 or 3

Therefore, the allowable condition is n=4, l=2, $m_{l}$ =2

To know more about quantum numbers, visit: brainly.com/question/16979660

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3 0

2 years ago

For the titration of 50. mL of 0.10 M ammonia with 0.10 M HCl, calculate the pH. For ammonia, NH3, Kb

Korolek [52]

Answer:

11.12 → pH

Explanation:

This is a titration of a weak base and a strong acid.

In the first step we did not add any acid, so our solution is totally ammonia.

Equation of neutralization is:

NH₃ + HCl → NH₄Cl

Equilibrium for ammonia is:

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻ Kb = 1.8×10⁻⁵

Initially we have 50 mL . 0.10M = 5 mmoles of ammonia

Our molar concentration is 0.1 M

X amount has reacted.

In the equilibrium we have (0.1 - x) moles of ammonia and we produced x amount of ammonium and hydroxides.

Expression for Kb is : x² / (0.1 - x) = 1.8×10⁻⁵

As Kb is so small, we can avoid the x to solve a quadratic equation.

1.8×10⁻⁵ = x² / 0.1

1.8×10⁻⁵ . 0.1 = x²

1.8×10⁻⁶ = x²

√1.8×10⁻⁶ = x → 1.34×10⁻³

That's the value for [OH⁻] so:

1×10⁻¹⁴ = [OH⁻] . [H⁺]

1×10⁻¹⁴ / 1.34×10⁻³ = [H⁺] → 7.45×10⁻¹²

- log [H⁺] = pH

- log 7.45×10⁻¹² = 11.12 → pH

4 0

3 years ago

If a gun is found in water, what should investigators do to transport it to the lab?

GREYUIT [131]

<span>Most items of evidence will be collected in paper containers such as packets, envelopes, and bags. Liquid items can be transported in non-breakable, leakproof containers. Arson evidence is usually collected in air-tight, clean metal cans. Only large quantities of dry powder should be collected and stored in plastic bags. Moist or wet evidence (blood, plants, etc.) from a crime scene can be collected in plastic containers at the scene and transported back to an evidence receiving area if the storage time in plastic is two hours or less and this is done to prevent contamination of other evidence. Once in a secure location, wet evidence, whether packaged in plastic or paper, must be removed and allowed to completely air dry. That evidence can then be repackaged in a new, dry paper container. UNDER NO CIRCUMSTANCES SHOULD EVIDENCE CONTAINING MOISTURE BE PACKAGED IN PLASTIC OR PAPER CONTAINERS FOR MORE THAN TWO HOURS. Moisture allows the growth of microorganisms which can destroy or alter evidence.

</span>

8 0

4 years ago

Read 2 more answers

How many 10 x 10 x 10” boxes Cane Bay pack into a crate that is 30 x 30 x 30

madam [21]

Answer:

its 3

3 x 10 = 30

-Hops

Explanation:

6 0

3 years ago

Read 2 more answers

Can someone help me answer this please

victus00 [196]

Answer:

A) 1.3 × 10⁻⁵ mol/L

Explanation:

Step 1: Write the balanced equation for the solution of AgCl

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

Step 2: Make an ICE Chart

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I 0 0

C +S +S

E S S

If we replace the solubility (S) in the Ksp expression, we get,

Ksp = [Ag⁺] [Cl⁻] = S × S = S²

S = √Ksp = √1.8 × 10⁻¹⁰ = 1.3 × 10⁻⁵ mol/L

6 0

3 years ago