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olga55 [171]
3 years ago
10

When this circuit is closed, which way do the electrons flow?

Physics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

- from the negative end of the battery through the capacitor through the resistors to the positive end

Explanation:

Here we know that battery is used to apply constant potential difference which will help to provide potential energy to the electric charge.

Now this charge will use this electric potential energy to move through higher potential region to lower potential region

here positive charge will always move from higher potential region to lower potential region while electron will move in opposite sense. So electron will always flow from lower potential point to higher potential point as it is negatively charged

so here the electron will start from negative terminal of battery and then goes to capacitor and then resistors and then finally move to positive terminal of the cell.

gizmo_the_mogwai [7]3 years ago
3 0

Answer:

from the positive end of the battery through the capacitor through the resistors to the negative end...

Current flows from higher potential (+) to lower potential (-)..

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A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's a
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A. Power generated by meteor = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Workdone = 981000 J

Power required = 19620 Watts

Note: The question is incomplete. A similar complete question is given below:

A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's atmosphere. As the drag force slows the meteor down, its kinetic energy is converted to thermal energy, leaving a glowing trail across the sky. A typical meteor has a surprisingly small mass, but what it lacks in size it makes up for in speed. Assume that a meteor has a mass of 1.5 g and is moving at an impressive 50 km/s, both typical values. What power is generated if the meteor slows down over a typical 2.1 s? Can you see how this tiny object can make a glowing trail that can be seen hundreds of kilometers away? 61. a. How much work does an elevator motor do to lift a 1000 kg elevator a height of 100 m at a constant speed? b. How much power must the motor supply to do this in 50 s at constant speed?

Explanation:

A. Power = workdone / time taken

Workdone = Kinetic energy of the meteor

Kinetic energy = mass × velocity² / 2

Mass of meteor = 1.5 g = 0.0015 kg;

Velocity of meteor = 50 km/s = 50000 m/s

Kinetic energy = 0.0015 × (50000)² / 2 = 1875000 J

Power generated = 1875000/2.1 = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Work done by elevator against gravity = mass × acceleration due to gravity × height

Work done = 1000 kg × 9.81 m/s² × 100 m

Workdone = 981000 J

Power required = workdone / time

Power = 981000 J / 50 s

Power required = 19620 Watts

Therefore, the motor must supply a power of 19620 Watts in order to lift a 1000 kg to a height of 100 m at a constant speed in 50 seconds.

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3 years ago
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