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Alla [95]
3 years ago
7

Which of the following is the best name for N2O? dinitrogen monoxide nitrogen monoxide nitrogen oxide nitrogen oxygen

Physics
2 answers:
Natasha_Volkova [10]3 years ago
5 0
A.) Di-nitrogen monoxide <span>is the best name for N2O

Hope this helps!</span>
8090 [49]3 years ago
3 0

dinitrogen monoxide........


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If the ball has a positive electric charge, what should the charge of the coilgun be to push the ball away?
Digiron [165]

Answer:

A

Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.

6 0
3 years ago
4. What is the amplitude of the waves shown in the diagram below?
densk [106]

Answer:

7.5 m

Explanation:

4 0
3 years ago
Lora (of mass 54 kg) is an expert skier. She
omeli [17]

The mechanical energy at top =Mechanical energy at bottom

  • Mass=m=54kg
  • Height=h=51m
  • Acceleration due to gravity=g=10m/s^2
  • Velocity=v=2.6m/s

\\ \tt\longmapsto M_{initial}=M_{Final}

  • Final energy at bottom=The kinetic energy

\\ \tt\longmapsto KE=M_{initial}

\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}

\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2

\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)

\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)

\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)

\\ \tt\longmapsto K .E=54(510+3.38)

\\ \tt\longmapsto K.E=54(513.38)

\\ \tt\longmapsto K.E=27722.52J

\\ \tt\longmapsto K.E=27.7KJ

6 0
2 years ago
Oysters are filter feeders. They get their food by moving large amounts of water through their bodies and filtering out whatever
Lynna [10]

A. Oysters, clams, and other shellfish are efficient filter feeders that help remove excess nitrogen from waters by incorporating it into their shells and tissue as they grow. ... Adult oysters reportedly can filter up to 50 gallons a day, while large quahogs (hard clams) can clean about 24 gallons of water a day

8 0
3 years ago
Calculate the electric field intensity at a point 3 cm away from point charge of 3 x 10^-9 C.
lukranit [14]

Answer:

The electric field intensity is <u>30000 N/C.</u>

Explanation:

Given:

Magnitude of the point charge is, q=3\times 10^{-9}\ C

Distance of the given point from the point charge is, d=3\ cm=0.03\ m

Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.

Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:

E=\frac{kq}{d^2}

Plug in k=9\times 10^9\ N\cdot m^2/C^2, q=3\times 10^{-9}\ C, d=0.03\ m. Solve for 'E'.

E=\frac{(9\times 10^9\ N\cdot m^2/C^2)(3\times 10^{-9}\ C)}{(0.03\ m)^2}\\\\E=\frac{27}{0.0009}\ N/C\\\\E=30000\ N/C

Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.

3 0
3 years ago
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