Answer:
8.0356 * 10^-5 moles of NaHCO3
Explanation:
Sulphuric acid = H2SO4
Sodium bicarbonate = NaHCO3
The reaction between both compounds is given by;
2NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
In the reactin above;
2 mol of NaHCO3 neutralizes 1 mol of H2SO4
At stp, 1 mol occupies 22.4 L;
1 mol = 22.4 L = 22400 mL
x mol = 0.9 mL
x = 0.9 / 22400 = 4.0178 * 10^-5 moles of H2SO4
Since 2 mol = 1 mol from the equation;
x mol = 4.0178 * 10^-5
x mol = 2 * 4.0178 * 10^-5
x = 8.0356 * 10^-5 moles of NaHCO3
Answer:
I
Explanation:
The complete question can be seen in the image attached.
We need to understand what is actually going on here. In the first step that yields product A, the sodamide in liquid ammonia attacks the alkyne and abstracts the acidic hydrogen of the alkyne. The second step is a nucleophilic attack of the C6H5C≡C^- on the alkyl halide to yield product B (C6H5C≡C-CH3CH2).
Partial reduction of B using the Lindlar catalyst leads to syn addition of hydrogen to yield structure I as the product C.
An atom of vanadium
(V) has 23 electrons.
Given :
A vanadium (V) atom with 23 protons and has a net charge of 0.
To find:
The number of electrons in a vanadium atom
Solution:
Number of protons in vanadium atom = 23
The 0 net charge on the atom indicates that the atom has an equal number of protons and electrons which makes it a neutral atom.
Number of electrons in vanadium atom = Number of protons in vanadium atom = 23
An atom of vanadium
(V) has 23 electrons.
Learn more about subatomic particles here:
brainly.com/question/7221719?referrer=searchResults
brainly.com/question/489853?referrer=searchResults
Answer:
<em>B) 12</em><em> </em><em>m/s</em>
Explanation:
s = 43km/1hr
s = 43,000m/3600sec
s = 11.94 m/s
s = 12 m/s
Answer:
A. True
Explanation:
Objects that are said to be undergoing free fall, are not encountering a significant force of air resistance; they are falling under the sole influence of gravity. Under such conditions, all objects will fall with the same rate of acceleration, regardless of their mass
