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3 years ago

What is the name of the following chemical compound?

Chemistry

1 answer:

Sati [7]3 years ago

3 0

Answer:

Beryllium fluoride

Explanation:

BeF2 is Beryllium fluoride

Hope this helps plz hit the crown :D

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Which of the following is NOT a binary molecular compound?<br> KI <br> H2s<br> CO<br> CIF3

shutvik [7]

I believe KI is not a a binary molecule.
Your welcome

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3 years ago

In a heat engine, 700 J of heat enters the system, and the piston does 400 J of work. What is the final internal (thermal) energ

Vitek1552 [10]

The first law of thermodynamics characterises the two types of energy transfer, as heat and as thermodynamic. The final internal (thermal) energy of the system is 1,500 J.

<h3>What is internal energy?</h3>

The energy present in a system itself for conducting reactions is called internal energy.

Given,

Heat entering system (Q) = 700 J
Work done by the piston (W) = 400
Initial energy $(\rm U_{1})$ = 1200 J

According to the <u>first law of thermodynamics</u>:

$\rm Q = \Delta U + W$

Substituting values in the above equation:

$\begin{aligned}\rm Q &= \rm U_{2} - U_{1} + W\\\\\rm U_{2} &= \rm Q - W + U_{1}\\\\\rm U_{2} &= 700 - 400 + 1200\\\\&= 1500 \;\rm J\end{aligned}$

Therefore, option D. 1500 J is the final energy.

Learn more about internal energy here:

brainly.com/question/2602565

4 0

2 years ago

Read 2 more answers

How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?

allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

<span>volume Na2S = 0.0212 L = 21.2 mL</span>

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3 years ago

Marking anybody who got it the brainliest

bija089 [108]

I can't open pdf.......

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2 years ago

A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3

IRINA_888 [86]

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram