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3 years ago

A pulse waveform with a frequency of 10 kHz is applied to the input of a counter. During 100 ms, how many pulses are counted?

Physics

1 answer:

bixtya [17]3 years ago

7 0

Answer:

n = 1000 pulses

Explanation:

Given that,

The frequency of a pulse waveform, $f=10\ kHz=10^4\ Hz$

To find,

The number of pulses counted during 100 ms.

Solution,

The frequency of a pulse waveform is equal to the number of pulses per unit time. It is given by :

$f=\dfrac{n}{t}$

$n=f\times t$

$n=10^4\ Hz\times 100\times 10^{-3}\ s$

n = 1000 pulses

So, there are 1000 pulses counted in a pulse waveform.

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Thought Experiment: A monkey escapes from a zoo and climbs a tree. After failing to entice the monkey down, a zookeeper fires a

Andreyy89

Explanation:

When bullet is shot towards the monkey then let say the distance of monkey from the bullet is "d"

so we can find the time to reach the bullet to the monkey

$t = \frac{d}{vcos\theta}$

Now similarly we can find the vertical displacement of the bullet in the same time

$\Delta y = vsin\theta t - \frac{1}{2}gt^2$

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$\Delta y = d tan\theta - \frac{1}{2}gt^2$

here if the monkey is initially at height H above the ground at given angle then we can say

$H = dtan\theta$

so we can say that

$\Delta y = H - \frac{1}{2}gt^2$

So if at the same time monkey will fall down then the height of monkey from ground after time "t" is given as

$\Delta y = H - \frac{1}{2}gt^2$

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2 years ago

Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo

defon

Answer:

$F = 26.04 N$

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

$F = (m_1 + m_2) a$

$m_1 = 24 kg$

$m_2 = 62 kg$

$F = 36 N$

$36 = (24 + 62) a$

$a = 0.42 m/s^2$

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

$F = ma$

$F = (62 \times 0.42)$

$F = 26.04 N$

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3 years ago