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Natali5045456 [20]
3 years ago
5

plssss help me !! Liquid water can be separated into hydrogen gas and oxygen gas through electrolysis. 1 mole of hydrogen gas an

d 0.5 moles of oxygen gas is produced from 1 mole of liquid water collected in separate 10 L containers at 1 atm. Will the temperatures of the gases be equal? In one to two sentences, use the ideal gas law to explain your answer.
Chemistry
1 answer:
Fantom [35]3 years ago
4 0

Answer:

I'm not sure but all I can find is this for you :)

The temperature of the oxygen gas is  243.75 K.

Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.

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Krafla Volcano in Iceland,

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4 years ago
Solid potassium chlorate decomposes upon heating to form
olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of  oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

V2 = 664.1052 ml

245.2   yielded 67.2 molar volume of oxygen

0.66411 will yield = \frac{245.2 * 0.66411}{67.2}  = 2.4232 g

percentage of potassium chlorate in the original mixture = \frac{2.4232 * 100}{7.44} = 32.6%

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3 years ago
I need help on this organic chemistry question:
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Selfmade.ivyy hope this help
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What trend is seen in atom size, going down the periodic table?
m_a_m_a [10]
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3 years ago
Find the pressure of a gas if the volume is 2.00 L, the temperature is 310 Kelvin and
kipiarov [429]

Answer:

25.42 atm

Explanation:

Data Given:

Volume of a gas ( V )= 2.00 L

temperature of a gas ( T ) =  310 K

number of moles (n) = 2​ mol

Pressure of a gas ( P ) = to be find

Solution:

Formula to be used

              PV= nRT

Rearrange the above formula

              P = nRT / V . . . . . . . . . . (1)

Where R is ideal gas constant

R = 0.08205 L atm mol⁻¹ K⁻¹

Put values in equation 1

                 P = nRT / V

                  P = 2 mol x 0.08205 L atm mol⁻¹ K⁻¹ x 310 k / 2 L

                  P = 50.84 L atm / 2 L

                  P = 25.42 atm

P ressure of gas (P) will be = 25.42 atm

7 0
4 years ago
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