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Natali5045456 [20]
2 years ago
5

plssss help me !! Liquid water can be separated into hydrogen gas and oxygen gas through electrolysis. 1 mole of hydrogen gas an

d 0.5 moles of oxygen gas is produced from 1 mole of liquid water collected in separate 10 L containers at 1 atm. Will the temperatures of the gases be equal? In one to two sentences, use the ideal gas law to explain your answer.
Chemistry
1 answer:
Fantom [35]2 years ago
4 0

Answer:

I'm not sure but all I can find is this for you :)

The temperature of the oxygen gas is  243.75 K.

Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.

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A magnet sticks to an iron can and an iron rod. This is an intrinsic property. <br> True or false?
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Answer:

True

Explanation:

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3 years ago
Which symbol represents a particle that has the same total number of electrons as S2-?
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The correct answer is D) Ar
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C= ( F - 32) / 1.8<br> 86 F = ?
egoroff_w [7]

<h3>⇒c =  \frac{f - 32}{1.8}</h3><h3>⇒c =  \frac{86 - 32}{1.8}</h3><h3>⇒c =  \frac{54}{1.8}</h3><h3>⇒c = 30</h3>

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7 0
2 years ago
Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di
pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)

Moles of calcium nitrate = \frac{31.3 g}{164 g/mol}=0.1908 mol

Moles of ammonium fluoride = \frac{38.7 g}{37 g/mol}=1.046 mol

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

\frac{1}{2}\times 1.046 mol=0.523 mol calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

\frac{2}{1}\times 0.1908 mol=0.3816 molof dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0
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If one or more of the following occur: Gas formation, precipitate formation, color change, temperature change, or odor

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