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MissTica
3 years ago
15

Photosynthesis is a chemical reaction where carbon dioxide and water react to form glucose (C6H12O6) and oxygen gas. Which repre

sents the proper balanced equations for photosynthesis? A) C6H12O6 + O2 → CO2 + H20 B) CO2 + H20 → C6H12O6 + O2 C) C6H12O6 + 6O2 → 6CO2 + 6H20 D) 6CO2 + 6H20 → C6H12O6 + 6O2
Physics
2 answers:
irga5000 [103]3 years ago
6 0
6CO2 + 6H2O --> C6H12O6 + 6O2  so D is the correct answer.
AnnyKZ [126]3 years ago
3 0
<span>Correct Answer: D) 6CO2 + 6H20 → C6H12O6 + 6O2</span>

The reactants are Carbon Dioxide (CO2) and Water (H2O) and the products are Glucose (C6H12O6) and Oxygen gas (O2).

In a balanced chemical equation, the number of atoms of each element are same on both left and right hand side of the equation. 

In the given options, option D gives the balanced chemical equation and mentions the reactants and products on correct sides of the equation. So the correct answer is Option D
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<em>Glad to help ya!! ;)</em>

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3 years ago
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3 years ago
Consider a horizontal layer of the dam wall of thickness dx located a distance x above the reservoir floor. What is the magnitud
adoni [48]

Answer:

Explanation:

Attached is the solution

6 0
3 years ago
1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the
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Answer:

v = 20.31 m/s

Explanation:

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4 0
3 years ago
A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an
olya-2409 [2.1K]

Answer:

289282

Explanation:

r = Radius of plate = 0.52 mm

d = Plate separation = 0.013 mm

A = Area = \pi r^2

V = Potential applied = 2 mV

k = Dielectric constant = 40

\epsilon_0 = Electric constant = 8.854\times 10^{-12}\ \text{F/m}

Capacitance is given by

C=\dfrac{k\epsilon_0A}{d}

Charge is given by

Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}

Number of electron is given by

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}

The number of charge carriers that will accumulate on this capacitor is approximately 289282.

6 0
3 years ago
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