All categories

3 years ago

Why is acetic anhydride added slowly to a dichloromethane solution of the other reactants?

2 answers:

8 0

Acetic anhydride is the only monocarboxylic acid anhydride which is an acylating agent capable of modifying reactions. The dichloromethane is the reaction solvent.

The acetic anhydride should be added slowly through a separatory funnel to other reactants so as to avoid a runaway reaction, also known as thermal runaway. By doing this the reaction mixture boils as gently as possible while stirring. This phenomenon occurs in situations where an increase in temperature changes the conditions in a way that leads to destructive result brought about by a further increase in temperature.

creativ13 [48]3 years ago

8 0

Acetic Acid is considered one of the excellent source of Acyl (CH₃CO-) group. It is also one of the the most reactive derivative of Carbonyl groups.

As we know that the bond formation is an Exothermic reaction. Greater the rate of formation of new bonds greater will be the amount of heat released.

Hence, Acetic Anhydride being more reactive will produce more heat on reaction with other reactants and generates more heat. In order to prevent the reaction mixture from bursting the reaction is often carried out at lower temperatures and also the rate of addition of Acetic Anhydride is slowed down.

You might be interested in

a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the

butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

$\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}$

Given ,

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7 ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (21.7 + 273.15) K = 294.85 K

T₂ = (28.1 + 273.15) K = 301.25 K

Using above equation as:

$\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}$

$\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K }}{0.998\ atm}$

$n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol$

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0

3 years ago

What kind of bond is formed when lithium and fluorine combine to form lithium fluoride?

cupoosta [38]

Answer:

ionic bond

Explanation:

4 0

3 years ago

Read 2 more answers

The proof that ch4 is a weak acid

boyakko [2]

Answer: because ch4 is not considered a acid they said it is too weak

Explanation:

8 0

3 years ago

Read 2 more answers

Is Bromothymol Blue acidic or basic?

notka56 [123]

It is mostly used in applications that need measuring substances that would have a relatively neutral pH . A common use is for measuring the presence of carbonic acid in a liquid. so yes its acidic

8 0

3 years ago

You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th

ASHA 777 [7]

Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially, only 4 moles of oxygen gas were present in the flask.

$p_{O_2}=Tp_1\times X_{O_2}$ ( $X_{O_2}=\frac{4}{4}$ ) ( according to Dalton's law of partial pressure)