Answer:
The value is 
Explanation:
From the question we are told that
The velocity which the rover is suppose to land with is 
The mass of the rover and the parachute is 
The drag coefficient is 
The atmospheric density of Earth is 
The acceleration due to gravity in Mars is 
Generally the Mars atmosphere density is mathematically represented as
=> 
=> 
Generally the drag force on the rover and the parachute is mathematically represented as
=> 
=> 
Gnerally this drag force is mathematically represented as
Here A is the frontal area
So
=> 
=>
Answer:
74.4 kilowatts or 99.8 horsepower
Explanation:
The explanation is in the attachment.
<span>3.92 m/s^2
Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so
0.4 * 9.8 m/s^2 = 3.92 m/s^2
If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so
20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N
Multiply by the coefficient of static friction, giving
196 N * 0.4 = 78.4 N
So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass
78.4 N / 20.0 kg
= 78.4 kg*m/s^2 / 20.0 kg
= 3.92 m/s^2
And you get the same result.</span>
Answer:
a
b
Explanation:
From the question we are told that
The mass of the person is 
The speed of the person is 
The energy of the proton is 
Generally the de Broglie wavelength is mathematically represented as
Here h is the Planck constant with the value
So
=>
Generally the energy of the proton is mathematically represented as
Here 
is the mass of proton with value 
=> 
=> 
=> 
So
so 
=>
