Parta a.
Equation: F = G*m1*m2/d^2
Where
F = 32 N
G = 6.67*10^-11 N.m^2/kg^2
m1 = 9.0*10^13kg
m2 =370 kg
d = distance that separate the center of the two objects.
d^2 = G*m1*m2 / F = 6.67*10^-11 N.m^2/kg^2 * 9.0*10^13 kg *370 kg / 32N = 69,409.69 m^2
d = √69,409.69m^2 = 263.5 m
Part B.
The gravitational field of the comet is g = G*m1/d^2
Notice that it does not depend on the mass of other objects.
Notice also that I will use a distance of 5.0 * 10^3 km, because I think that that is the number that you intended to write in the part b. If that is not the number you can put the right number instead because the solution is written step by step.
g = (6.67*10^-11 N*m^2/kg^2)*(9.0*10^13kg)/(5.0*10^3*10^3m)^2 = 2.4*10^-4 N/kg = 2.4*10^-4 m/s^2
Answer:
f2 = 140 Hz
Explanation:
let fundamental frequency is f1 = 70.0 Hz
formula for finding the higher frequency when fundamental frequency is known
fn = n f1 (where f1 is fundamental frequency and n = 1,2,3,4,5...........)
for the second frequency n=2
f2 = 2 × 70.0 Hz
f2 = 140 Hz
0 N. It's being pushed up the same amount it's being pushed down, so it cancels out.
Answer:
The tension is 14 N
Explanation:
For this problem we have to use newton's law, so:
The second string is connected to the mass of 8 kg, but the mass of 8 kg is connected to the mass of 20kg, so we can say that the second string is handling the two masses. so:
-981N would be the reaction force of a person be that stands completely still with a mass of 100 kg.
An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction. Usually, the activities of applied forces result in reaction forces and reaction moments.
As,
F = ma
where, F = force
m = mass of object
a = acceleration due to gravity
Plugging in the values we get,
F = 100kg × 9.81m/s
F = 981 N
Since, reaction force acts opposite to action force so the correct answer is -981N.
Learn more about force here;
brainly.com/question/13191643
#SPJ4
