The height of the ball above the ground is 38.45 m
First we will calculate the velocity of the ball when it touch the ground by using first equation of motion
v=u+gt
v=0+9.81×2.8
v=27.468 m/s
now the height of the ground can be calculated by the formula
v=√2gh
27.468=√2×9.81×h
h=38.45 m
Answer:
78.4 m
Explanation:
To obtain the height of the cliff;
We can use the Relation to obtain the final velocity, v
v = u + at
a = acceleration due to gravity = 9.8m/s²
v = 0 + (9.8*4)
v = 0 + 39.2
v = 39.2 m/s
To obtain the Height, S
v² = u² + 2aS
39.2^2 = 0 + 2(9.8)S
39.2^2 = 0 + 19.6S
1536.64 = 19.6S
S = 1536.64 / 19.6
S = 78.4 m
A heavy weight suspended within a moving box needs to overcome inertia, resulting in a slight delay in the motion of the weight after the box moves. <u>Option B.</u>
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The principle underlying the construction of a seismometer is to have a heavy weight suspended from a spring on a pedestal or inside a movable box. A seismograph is an instrument that records and measures the details of an earthquake. A seismograph uses a seismograph to record data.
Elastic deformation bends an object, whereas repulsion returns it to its original shape. This instrument is nothing more than an oscillating rod or pendulum that begins to vibrate when a tremor occurs. The vibration system has a pin. The pen records seismic waves on a sheet of paper that moves underneath. By studying these waves scientists can create a complete map of earthquakes.
Learn more about Seismograph construction here:-brainly.com/question/16047884
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