If a car travels 80 miles between 2 and 4 pm, then its velocity is close to 40 mph at 2 pm.
1 answer:
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Answer:
zero
Explanation:
q = 6.4 nC = 6.4 x 1 0^-9 C
d = 16 cm = 0.16 m
r = 16 / 2 = 8 cm = 0.08 m
Electric field at P due to the charge placed at A
Ea = k q / r^2
Ea = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards right
Ea = 9000 Towards right
Electric field at P due to the charge placed at B
Eb = k q / r^2
Eb = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards left
Eb = 9000 Towards left
The magnitude of electric field is same but teh direction is opposite, so the resultant electric field at P is zero.
Answer:
Explanation:
The capacitance of the parallel-plate capacitor is given by
where
ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity
k = 3.00 is the dielectric constant
is the area of the plates
d = 9.00 mm = 0.009 m is the separation between the plates
Substituting,
Now we can calculate the energy of the capacitor, given by:
where
C is the capacitance
V = 15.0 V is the potential difference
Substituting,