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3 years ago

What do you mean by momentum?

1 answer:

7 0

The answer to this question is that --- The momentum possessed by a body is generally defined as the product of its mass and velocity.

Momentum is a vector and it also has magnitude as it is the product of the multiplication of the mass and velocity.

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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.

serg [7]

Well formation of metallic bond depends on free electrons.smaal sized atoms hold their electrons more firmly as compared to large size atoms ,this z due to distance of outer shell electrons by nucleus..in this way no of free electrons affect strength of metallic bond..smaal sized atoms release less free electrons..

8 0

4 years ago

Read 2 more answers

If a 0.5 kg pair of running shoes would weigh 11.55 Newton’s on Jupiter, what is the strength of gravity there?

OverLord2011 [107]

The weight of an object is given by
$F=mg$
where m is the mass of the object, while g is the strength of the gravity (which corresponds to the gravitational acceleration of the planet).

In our problem, the shoes have a mass of m=0.5 kg, and their weight is F=11.55 N. So, we can re-arrange the previous formula to find the value of g:
$g= \frac{F}{m}= \frac{11.55 N}{0.5 kg}=23.1 N kg^{-1}$
and this is the strength of the gravity on Jupiter's surface.

4 0

3 years ago

When antimatter interacts with an equal mass of ordinary matter, both matter and antimatter are converted completely into energy

Ilya [14]

Answer:

v = 5.88 10⁷ m / s

Explanation:

For this exercise we use the relation

E = m c²

also indicate that all energy is converted into kinetic energy

E = K = ½ (M-2m) v²

where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined

we substitute

m c² = ½ (M-2m) v²

v² = $2 \frac{m}{M+2m} \ c^2$

let's calculate

v = $\sqrt{2 \ \frac{4 \ 10^4 }{2 \ 10^6 + 2 \ 4 \ 10^4} \ (3 \ 10^8)^2}$

v = $\sqrt{ 34.615 \ 10^{14}}$

v = 5.88 10⁷ m / s

8 0

3 years ago

Calculate the gravitational potential energy relative to the ground when an 82 kg person climbs to the top of a 2.0 m stepladder

bezimeni [28]

Maybe 164.... not to sure though, sorry

6 0

3 years ago

If we put negative charge between two similar positive charges then what is it's equilibrium? And how?

Gnesinka [82]

Your question has been heard loud and clear.

Well it depends on the magnitude of charges. Generally , when both positive charges have the same magnitude , their equilibrium point is towards the centre joining the two charges. But if magnitude of one positive charge is higher than the other , then the equilibrium point will be towards the charge having lesser magnitude.

Now , a negative charge is placed in between the two positive charges. So , if both positive charges have same magnitude , they both pull the negative charge towards each other with an equal force. Thus the equilibrium point will be where the negative charge is placed because , both forces are equal , and opposite , so they cancel out each other at the point where the negative charge is placed. However if they are of different magnitudes , then the equilibrium point will be shifted towards the positive charge having less magnitude.

Thank you

5 0

4 years ago

Read 2 more answers