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4 years ago

Please Answer ASAP

Chemistry

2 answers:

aalyn [17]4 years ago

4 0

Answer:

The correct answer is option C.

Explanation:

Empirical formula is the simplest chemical formula which tells us the whole number of atoms of each element present in the compound.

For $S_4O_2[/tex[ the empirical formula will be: [tex]S_{\frac{4}{2}}O_{\frac{2}{2}}=S_2O$

For $SO_4[/tex[ the empirical formula will be: [tex]S_{\frac{1}{1}}O_{\frac{4}{1}}=SO_4$

For $S_2O_6[/tex[ the empirical formula will be: [tex]S_{\frac{2}{2}{2}O_{\frac{6}{2}}=SO_3$

For $S_2O_3[/tex[ the empirical formula will be: [tex]S_{\frac{2}{2}{1}O_{\frac{3}{1}}=S_2O_3$

Hence, the correct answer is option C.

adelina 88 [10]4 years ago

3 0

The answer to this question would be S2o6 which is C.

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State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne

saveliy_v [14]

Answer:

Ne 20: 10

and

Ne 22: 12

Explanation:

Ne-20:

N = A - Z = 20 - 10 = 10 neutrons

Ne-22:

N = A - Z = 22 - 10 = 12 neutrons

N: number of neutrons

A: mass number

Z: atomic number

8 0

3 years ago

Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N

Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of $NaN_3$

$\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}$

Molar mass of $NaN_3$ = 65.01 g/mole

$\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole$

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NaN_3$ react to give 3 mole of $N_2$

So, 0.311 moles of $NaN_3$ react to give $\frac{0.311}{2}\times 3=0.466$ moles of $N_2$

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = ?

n = number of moles $N_2$ = 0.466 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $22^oC=273+22=295K$

Putting values in above equation, we get:

$1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K$

$V=11.3L$

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0

3 years ago

Which of the following is true about nuclear fusion

Sonja [21]

Answer:

i would assume that it would be (a)

Explanation:

The Sun generates its energy by nuclear fusion

NUCLEAR FISSION is when the heavy atom is split

fusion energy is scientifically feasible. Plasma conditions that are very close to those required in a fusion reactor are now routinely reached in experiments

mass gets lost is nuclear fusion

so (a) is the most accurate

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3 years ago

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Rudik [331]

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3 years ago

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If an object is accelerating at a rate of 25 m/s2, how long (in seconds) will it take to reach a speed of 550 m/s? (Assume an in

V125BC [204]

Answer:

22s

Explanation:

Given parameters:

Acceleration = 25m/s²

Final velocity = 550m/s

Initial velocity = 0m/s

Unknown:

Time taken = ?

Solution:

To solve this problem, we are going to use one of the motion equations:

v = u + at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

550 = 0 + 25 x t

550 = 25t

t = 22s

8 0

3 years ago