How is water molecule like a magnet?

1 answer:

5 0

Water molecules hydrogen bond with neighboring water molecules. Hydrogen bonding is very strong. The partial positive of the oxygen attracts the partial positive of the hydrogen so they bind to each other.

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A moving hammer hits a nail and drives it into a wall. if the hammer hits the nail with twice the speed, how much deeper will th

vlabodo [156]

This is an example of work-energy theorem where it lets a person accumulate the strength of the muscles over the duration of the swing, allowing much bigger forces as the hammer hits the nail.
Moreover, the work done on an object by a net force is equals to the change in kinetic energy of the object, which is expressed as W = KEf - KEi. 
Therefore, if the hammer hits the nail with twice the speed, it corresponds to 4 times the energy and four times the driving distance. If the hammer hits with three times the speed, the driving distance is 9 times as much.

5 0

3 years ago

If the frequency of the 13C signal of TMS is 201.16 MHz, the two 13C signals of acetic acid at 179.0 and 20.0 ppm are separated

Lelu [443]

The difference in frequency of the two signals is $1.33 \times 10^{10} \ kHz$ .

The given parameters;

frequency of the 13 C signal = 201.16 MHz

The energy of the 13 C signal located at 20 ppm is calculated as follows;

$E = hf\\\\E_1 = h \frac{c}{\lambda} \\\\E_1 = \frac{(6.626 \times 10^{-34})\times 3\times 10^8}{20 \times 10^{-6}} \\\\E_1 = 9.94 \times 10^{-21} \ J$

The energy of the 13 C signal located at 179 ppm is calculated as follows;

$E_2 = \frac{hc}{\lambda} \\\\E_2 = \frac{(6.626\times 10^{-34})\times (3\times 10^{8})}{179 \times 10^{-6} } \\\\E_2 = 1.11 \times 10^{-21} \ J$

The difference in frequency of the two signals is calculated as follows;

$E_1- E_2 = hf_1 - hf_2\\\\E_1 - E_2 = h(f_1 - f_2)\\\\f_1 - f_2 = \frac{E_1 - E_2 }{h} \\\\f_1 - f_2 = \frac{(9.94\times 10^{-21}) - (1.11 \times 10^{-21})}{6.626\times 10^{-34}} \\\\f_1 - f_2 = 1.33 \times 10^{13} \ Hz\\\\f_1 - f_2 = 1.33\times 10^{10} \ kHz$