1. Acceleration
2. If you are going 12 meters per second and you want to know how many seconds it takes yo get to 105 meters, you need yo find how long it takes to go horizontally then vertically. 12 seconds.
3. B

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3 years ago

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A uniform, solid sphere of radius 3.75 cm and mass 4.00 kg starts with a purely translational speed of 1.75 m/s at the top of an

puteri [66]

Answer:

v_2=4.53m/s $v_2=4.53m/s$

Explanation:

In order to solve the exercise it is necessary to apply the energy conservation equation,

The equation says the following,

$mgdsin(\theta)+\frac{1}{2}mv^2_1=\frac{1}{2}mv^2_2+\frac{1}{2}Iw^2$

Replacing the formula for I of a sphere, we have

$mgdsin(\theta)+\frac{1}{2}mv^2_1=\frac{1}{2}mv^2_2+\frac{1}{2}\frac{2}{5}mr^2(\frac{v_2}{r})^2$

$mgdsin(\theta)+\frac{1}{2}mv^2_1=\frac{1}{2}mv^2_2+\frac{1}{5}mv^2_2=\frac{7}{10}mv^2_2$

$\frac{10}{7}gdsin(\theta)+\frac{5}{7}v^2_1=v^2_2$

In this way we get the expression

$v_2=\sqrt{\frac{10}{7}gdsin(\theta)+\frac{5}{7}v^2_1}$

We proceed to replace with the given values and obtain that

$v_2=\sqrt{\frac{10}{7}*9.8*3sin(26))+\frac{5}{7}*1.75^2}$

$v_2=4.53m/s$

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3 years ago

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Count the dots to make sure that all of the valence electrons are represented 2

Semenov [28]

Do you have a diagram or anything?

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3 years ago