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GalinKa [24]
3 years ago
9

Which type of air mass forms over the ocean near the equator?

Physics
2 answers:
Ronch [10]3 years ago
7 0
The answer is A. Moist and Warm
grin007 [14]3 years ago
4 0

Answer:

a

Explanation:

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In a 2-dimensional coordinate system, the x- and y-axes are typically _____.
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<span>In a 2-dimensional coordinate system, the x- and y-axes
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What happends when you slowly pull out the paper while theirs a coin on top​
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Assume the space shuttle's main engines produce 764,576 newtons of thrust, and the shuttle has a mass of 78,018 kg. Why does the
Nady [450]

Weight of anything = (mass) x (gravity in the place where the thing is)

Weight of anything on Earth = (mass) x (9.81 m/s²)

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Weight of the shuttle, on Earth = 765,357 Newtons

Thrust of main engines = 764,576 Newtons

Are you starting to see the problem yet ?

The weight of the whole thing standing on the launch pad is 751 Newtons more than the maximum thrust of the main engines, and the engines can't lift it !  Even with all throttles wide open, the main engines alone would need about 175 <em>more</em> pounds of thrust to budge that load off the ground.  Even with the pedal to the metal, with flame and smoke belching out and covering the whole launch complex, the shuttle would just sit there and never leave the pad.

Well, no.  That's not exactly what would happen.  As the fuel in the main monster fuel tank is burned, the weight decreases.  So it would actually happen like this:  After the man announced "Zero !  We have ignition !  All engine running !", the ship would just sit there on the pad ... at first.  It would go nowhere and not even wiggle, <em>UNTIL</em> the first 175 pounds of fuel got burned without accomplishing anything.  The ship would then be 175 pounds lighter.  At that point, the weight would be exactly equal to the thrust of the main engines, and the vertical forces on the ship would be balanced.  Then, as MORE fuel continued to be wasted and the weight continued to decrease, the main engines could just begin to lift the ship off the pad.

So the correct answer is <em>choice-D</em> .  It tells the whole story, quicker than I can tell it.

4 0
3 years ago
A man runs 800m due north in 110 seconds followed by 400m due suoth in 90 seconds calculate his average speed and his average ve
andrey2020 [161]

Answer:

Average speed is  6m/s

Average velocity is 5.859m/s

Explanation:

Average speed, s = d/t

d is distant

t is time

speed north is 800m and 110s

speed due south is 400m and 90s  

Average speed = (800+400) / (110+90)

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Average velocity V = (v + u)/2

v = final velocity

u = initial velocity

V = (7.273 + 4.444)/2 = 11.717/2

V = 5.859m/s

6 0
3 years ago
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