Answer:
aluminum forms a complex ion with excess hydroxide
Explanation:
Complex formation accounts for the dissolution of certain compounds. For instance,reaction of aluminum and sodium hydroxide yields insoluble aluminum hydroxide as follows;
Al(s) + 3NaOH(aq) -----> Al(OH)3(s) +Na(s)
However, in excess NaOH, the solid aluminum hydroxide dissolves as due to the formation of a complex Al(OH)4^- in the solution.
Answer:
(a) 1:3
(b)
mmol of OH⁻ = 1.893 mmol
mmol of H₃C₆H₅O₇: 0.6310 mmol
mass of H₃C₆H₅O₇: 0.1212 g
mass % of H₃C₆H₅O₇ in orange juice: 1.37%
molarity of H₃C₆H₅O₇ in orange juice: 0.0726 M
Explanation:
Let's consider the following balanced chemical equation.
H₃C₆H₅O₇ + 3 OH⁻ → C₆H₅O₇³⁻ + 3 H₂O
<em>(a) What is the stoichiometry of H₃C₆H₅O₇ to OH⁻? </em>
The molar ratio of H₃C₆H₅O₇ to OH⁻ is 1:3
<em>(b)</em>
<em>mmol of OH⁻: ?</em>

<em>mmol of H₃C₆H₅O₇: ?</em>

<em>mass of H₃C₆H₅O₇: ?</em>
The molar mass of the citric acid is 192.1 g/mol.

<em>mass % of H₃C₆H₅O₇ in orange juice: ?</em>

<em>molarity of H₃C₆H₅O₇ in orange juice: ?</em>

Answer:
Match the words to the definitions.
Explanation:
1. F
2. A
3. C
4. E
5. B
6. D
7. B
8. F
9. A
10. E
11. D
12. C
13. B
Answer :
2 red : 2 white
Explanation:
;)long story short
hetro with hetro gives 3:1
hetro with recessive gives 1:1
Hetro :- ( Rr) one capital letter and one small
Recessive :- (rr) two small leters