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zubka84 [21]
3 years ago
14

What is the charge for MnO4

Chemistry
1 answer:
lakkis [162]3 years ago
3 0

Answer:

Mn = 2+, O = -2

Explanation:

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What is the density of a substance with a mass of 0.0450 and a volume of 26.4?
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Answer:

density \:  =  \frac{mass}{volume}  \\  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{0.0450}{26.4}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \: = 0.0017 \\

Explanation:

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Polonium-208 undergoes alpha decay. In addition to the alpha
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Explanation:

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Two hydrogen atoms interact to form a hydrogen molecule. Classify the following statements that describe the stages of bond form
shtirl [24]

Answer:

Attractive force is predominant between the two atoms

  • The two hydrogen atoms approach each other to form a bond
  • The two hydrogen atoms start to combine to form a hydrogen molecule

Repulsive force is predominant between the two atoms

  • The potential energy of the system is positive
  • The internuclear distance between the two hydrogen atoms is less than the bond length

Attractive and repulsive forces balance each other

  • The two hydrogen atoms form a stable hydrogen molecule
  • The potential energy of the system is at minimum

There is no interaction between the two atoms

  • The hydrogen atoms are very far apart

Explanations:

  • <em>increase in potential energy causes repulsion</em> between the atoms, whereas<em> decrease in potential energy causes attraction</em> between the atoms
  • in order for the bonding to occur, the attractive forces must be greater than the repulsion forces.
  • The potential energy is positive when the repulsion forces is greater. This is because the distance between the two atoms is smaller than the bond length
  • The potential energy of the system is at its minimum because the attractive and repulsive forces balance out each other.
3 0
3 years ago
Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the numbe
yuradex [85]

Answer:

The ratio of pressure in bottle B to that of bottle A is 1 : 4

Explanation:

We'll be by calculating the pressure in both bottles. This is illustrated below below:

For A:

Temperature (T) = T

Volume (V) = V

Number of mole (n) = n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

PV = n x 0.0821 x T

Divide both side by V

P = nT0.0821/V

Therefore, the pressure, in bottle A is

PA = nT0.0821/V

For B:

Temperature (T) = the same as that of A = T

Volume (V) = twice that of A = 2V

Number of mole (n) = half that of A = ½n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

P x 2V = ½n x 0.0821 x T

Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

PB = nT0.0821/4V

Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

Pressure in bottle A (PA) = nT0.0821/V

Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.

3 0
4 years ago
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