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belka [17]
3 years ago
5

Why isn’t a bird sitting on a high-voltage power line electrocuted? Contrast this with the situation in which a large bird hits

two wires simultaneously with its wings
Physics
2 answers:
Grace [21]3 years ago
8 0

Answer:

The reason the bird is not electrocuted is due to some facts about circuit:

1. Completeness of circuit- This circuit needs to be

complete in order for current to flow. The bird standing on only one wire has not completed the circuit.

2. A potential difference: Another factor deciding

the direction of flow of current is (electric)

potential. Current always flows from a higher

potential to a lower potential. In other words it

can be said that electrons flow from lower

potential to higher one. (the direction of electric

current is opposite to that of the electrons). So

we need the potential difference for current to

flow. The bird standing on only one wire has no potential difference.

3. Path of least Resistance- Factor that decides

the path a current will flow in case of parallel

paths is the (electric) resistance offered by the

path. Current will always flow in the path that

offers least resistance. The leg of a bird has high resistance.

Explanation:

It has no potential difference as both the legs of bird are touching the same wire at same constant potential. ... If the bird would touch the ground while sitting on the wire or flap its wings and touch another electric wire with a different voltage, then it would get shocked and likely die by electrocution.

while in the other hand, the Bird that touches two wires with it wings at the same time will get electrocuted because it has completed a circuit and the its feathers created a potential difference .

belka [17]3 years ago
6 0

Answer:

A) The main reason why a bird sitting on a high voltage power line is not electrocuted is because for current to flow, there has to be a complete circuit with an electric potential in the path of least resistance and in this case the conditions for electric to flow are not met.

B) In contrast to A above, when the bird hits two wires simultaneously with it's wings while sitting, it would get shocked and most likely die by electrocution.

Explanation:

A) The main reason why a bird sitting on a high voltage power line is not electrocuted is because for current to flow, there has to be a complete circuit with an electric potential in the path of least resistance. In this case, the circuit isn't complete because the bird is not in contact with another wire which is needed to complete a circuit and thus has no electric potential because both of it's legs are touching the same wire at same constant potential and also at this point, even though there is very little electric flow, it is negligible and not able to harm the birds due to strong resistance to electric flow because the wires are usually good conductors of electricity.

B) In contrast to A above, when the bird hits two wires simultaneously with it's wings while sitting, it would get shocked and most likely die by electrocution if the wire is of different voltage from the one it sits because it's body through it's wings has now become a path for electricity to flow to another wire of different Voltage.

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*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
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Answer:

Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

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2 years ago
When aluminum foil is formed into a loose ball, it can float on water. But when the ball of foil is pounded flat with a hammer,
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What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o
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The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.

<h3>What is the force exerted on the charge?</h3>

Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.

when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.

Mathematically the force exerted on the charge will be

F=qvBsinα

F= force acting on the charge

v = velocity of charge

q = charge

F=qvBsinα

F=2.5×10⁻⁶×5.0×10³×3.0×10²

F=37.5 N

Hence The force acting on the charge will be 3.75 N.

To learn more about the force acting on charge refer to ;

brainly.com/question/451411

F = q V B sinα

Where F is the force applied to a moving charge.

V = charge velocity

q stands for charge.

α = angle between V and B directions

As a result, the moving charge is subjected to a force of 3.75 Newton.

3 0
1 year ago
A motorcycle has 100,000 J of kinetic energy and is traveling at 20 m/s. Find its mass.
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Answer:

<h3>The answer is 500 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{2KE}{ {v}^{2} }  \\

v is the velocity

KE is the kinetic energy

From the question we have

m =  \frac{2 \times 100000}{  {20}^{2}  }  =  \frac{200000 }{400} =   \frac{2000}{4}  \\

We have the final answer as

<h3>500 kg</h3>

Hope this helps you

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