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Vesnalui [34]
3 years ago
11

When sunlight excites electrons in chlorophyll, how do the electrons change?

Physics
1 answer:
Rufina [12.5K]3 years ago
5 0

When the sunlight hits the electrons in the chlorophyll, these electrons would change by increasing its energy level. Then the electrons would move from one molecule to another in the thylakoid membrane, thus making the plant replenish its electrons using water energy.

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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to
earnstyle [38]

The correct answer to the question is : D) 352.6 m/s.

CALCULATION :

As per the question, the temperature is increased from 30 degree celsius to 36 degree celsius.

We are asked to calculate the velocity of sound at 36 degree celsius.

Velocity of sound is dependent on temperature. More is the temperature, more is velocity of sound.

The velocity at this temperature is calculated as -

                            V = 331  + 0.6T m/s

                               = 331 + 0.6 × 36 m/s

                               = 331 + 21.6 m/s

                               = 352.6 m/s.

Here, T denotes the temperature of the surrounding.

Hence, velocity of the sound will be 352.6 m/s.

5 0
4 years ago
Read 2 more answers
What factors affect the frictional force between objects ?
g100num [7]
Well it should be Material and weight not sure 
4 0
3 years ago
In a ____ wave, pasticles of the medium move perpendicular<br> to the direction of the wave.
GrogVix [38]
The answer is transverse
6 0
3 years ago
Directions: Read each question carefully and answer
Lady bird [3.3K]
I have all the answers here so take this

8 0
2 years ago
A truck is traveling 70.0 kph away from you. The driver is blowing the horn, which has a frequency of 400 Hz. The air temperatur
mr_godi [17]
There are several information's already given in the question. Based on those information's the answer can be easily deduced.
Speed of the truck = 70 kph
                              = 19.44 m/s
Speed of sound = 343 m/s
Then
Observed frequency = 400 Hz ∗ 343 m/s/<span>19.44m/s + 343 m/<span>s
                                 = 378.54
                                 = 379 Hz</span></span>
4 0
4 years ago
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