Answer:
The answer to your question is 27.3 %
Explanation:
Percent by mass = ?
Process
1.- Calculate the atomic mass of carbon using the periodic table
Atomic mass = 12g
2.- Calculate the molecular mass of CO₂.
Carbon = 12
Oxygen = 16 x 2 = 32
Total = 12 + 32 = 44g
3.- Calculate the percent by mass of carbon using proportions
44g -------------------- 100%
12 g ------------------- x
x = (12 x 100) / 44
x = 1200 / 44
x = 27.3 %
When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3
Answer:
increase , my age increase
Explanation:
hope it helps..
464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>
Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :
